Question

A gas expands from a volume of 2.00L at 36.0oC to a volume of 2.50 L, what is the final temperature, if the pressure is constant?

Answer 1

We shall consider V, the volume and T, the temperature.
According to Boyle's Laws:
$\frac{V1}{T1} = \frac{V2}{T2}$
In our case:
$\frac{2.00}{36.0} = \frac{2.50}{T2} =\ \textgreater \ T2= \frac{2.50*36.00}{2.00} = 45$

Answer 2

The final temperature is 45.45 Celcius

Explanation:

The Combined Gas Law:

The combined gas law allows to derive relationships between  the variable that undergoes like pressure, temperature and volume.

$\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}$

It is given thatpressure is constant so,

$P_1=P_2$

Hence combined gas law becomes,

$\frac{ V_1}{T_1}=\frac{V_2}{T_2}$

Substituting the values given in the question,

$\frac{2.00}{36}=\frac{2.50}{T_2}$

$0.055=\frac{2.50}{T_2}$

$T_2=\frac{2.50}{0.055}$

$T_2$=45.45 C