All categories

2 years ago

Can u solve it i dunno how:)

Mathematics

2 answers:

pshichka [43]2 years ago

6 0

Answer:

Step-by-step explanation

I think it is $170 a month.

Is subtracted 8,500-6,460 and that gave me 2,040.

I divided that by 12 and it gave me 170

s344n2d4d5 [400]2 years ago

6 0

Answer:

First answer: $170 per month

Second answer: 50 months, or 4 years and 2 months

Step-by-step explanation:

Step 1: Find out how much he paid in the first year. He started with $8500 in debt and after the first year his debt was down to $6460, subtract $6460 from $8500...

$8500 - $6460 = $2040

So he paid $2040 in the first year. Divide that by 12 to see how much he paid per month.

$2040/12 = $170 per month

Step 2: Find out how many months it takes him to pay back the full $8500. Divide $8500 by $170

$8500/$170 = 50

So 50 months, or 4 years and 2 months

You might be interested in

Can you helpppp pleasse

ryzh [129]

Answ 456

Step-by-step explanation:

ask your mom she might know unless she is to craycray

7 0

3 years ago

Ples help me find slant assemtotes

FrozenT [24]

A polynomial asymptote is a function $p(x)$ such that

$\displaystyle\lim_{x\to\pm\infty}(f(x)-p(x))=0$

$(y+1)^2=4xy\implies y(x)=2x-1\pm2\sqrt{x^2-x}$

Since this equation defines a hyperbola, we expect the asymptotes to be lines of the form $p(x)=ax+b$ .

Ignore the negative root (we don't need it). If $y=2x-1+2\sqrt{x^2-x}$ , then we want to find constants $a,b$ such that

$\displaystyle\lim_{x\to\infty}(2x-1+2\sqrt{x^2-x}-ax-b)=0$

We have

$\sqrt{x^2-x}=\sqrt{x^2}\sqrt{1-\dfrac1x}$
$\sqrt{x^2-x}=|x|\sqrt{1-\dfrac1x}$
$\sqrt{x^2-x}=x\sqrt{1-\dfrac1x}$

since $x\to\infty$ forces us to have $x>0$ . And as $x\to\infty$ , the $\dfrac1x$ term is "negligible", so really $\sqrt{x^2-x}\approx x$ . We can then treat the limand like

$2x-1+2x-ax-b=(4-a)x-(b+1)$

which tells us that we would choose $a=4$ . You might be tempted to think $b=-1$ , but that won't be right, and that has to do with how we wrote off the "negligible" term. To find the actual value of $b$ , we have to solve for it in the following limit.

$\displaystyle\lim_{x\to\infty}(2x-1+2\sqrt{x^2-x}-4x-b)=0$

$\displaystyle\lim_{x\to\infty}(\sqrt{x^2-x}-x)=\frac{b+1}2$

We write

$(\sqrt{x^2-x}-x)\cdot\dfrac{\sqrt{x^2-x}+x}{\sqrt{x^2-x}+x}=\dfrac{(x^2-x)-x^2}{\sqrt{x^2-x}+x}=-\dfrac x{x\sqrt{1-\frac1x}+x}=-\dfrac1{\sqrt{1-\frac1x}+1}$

Now as $x\to\infty$ , we see this expression approaching $-\dfrac12$ , so that

$-\dfrac12=\dfrac{b+1}2\implies b=-2$

So one asymptote of the hyperbola is the line $y=4x-2$ .

The other asymptote is obtained similarly by examining the limit as $x\to-\infty$ .

$\displaystyle\lim_{x\to-\infty}(2x-1+2\sqrt{x^2-x}-ax-b)=0$

$\displaystyle\lim_{x\to-\infty}(2x-2x\sqrt{1-\frac1x}-ax-(b+1))=0$

Reduce the "negligible" term to get

$\displaystyle\lim_{x\to-\infty}(-ax-(b+1))=0$

Now we take $a=0$ , and again we're careful to not pick $b=-1$ .

$\displaystyle\lim_{x\to-\infty}(2x-1+2\sqrt{x^2-x}-b)=0$

$\displaystyle\lim_{x\to-\infty}(x+\sqrt{x^2-x})=\frac{b+1}2$

$(x+\sqrt{x^2-x})\cdot\dfrac{x-\sqrt{x^2-x}}{x-\sqrt{x^2-x}}=\dfrac{x^2-(x^2-x)}{x-\sqrt{x^2-x}}=\dfrac
 x{x-(-x)\sqrt{1-\frac1x}}=\dfrac1{1+\sqrt{1-\frac1x}}$

This time the limit is $\dfrac12$ , so

$\dfrac12=\dfrac{b+1}2\implies b=0$

which means the other asymptote is the line $y=0$ .

4 0

3 years ago

In need of help! find the value of x

DaniilM [7]

∆= 180°
180°-(62°+58°)= ?
180°-120°=60°

a line = 180° on both sides.
180°-60°=X
120°=X

3 0

3 years ago

In Circle O, centrally angle AOB measures π/3 radians.What is the length of arc AB?

Oksanka [162]

Answer:

$s=r*\pi /3$

Step-by-step explanation:

The length of any arc is calculated using the following equation:

s = r*θ

Where s is the length of the arc, r is the radius of the circle and θ is the angle in radians.

So, if we have a Circle O and a centrally angle AOB that measures π/3 radians, the value of the length of arc AB is calculated as:

$s=r*\pi /3$

Where r is the radius of the circle O.

5 0

3 years ago

This two-way frequency table shows the results of a survey of users of the mass-transit system in a city. People were asked thei

lora16 [44]

Answer:

if Q={1,3,5,7,9}Express it in description methods

6 0

3 years ago

Can u solve it i dunno how:)​

Can u solve it i dunno how:)