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Nastasia [14]
3 years ago
11

Which table shows a proportional relationship ?? Pls help

Mathematics
1 answer:
Iteru [2.4K]3 years ago
8 0

Answer:

Option 2

Step-by-step explanation:

If you multiply 2 by 2 you get 4. If you multiply 3 by 2 you get 6. If you multiply 4 by 2, you get 8. If you multiply 5 by 2 you get 10. A proportional relationship is where you can multiply all the numbers by a certain number to get the answer. In this case, all the numbers in the left column could get multiplied by 2 to get the number in the right column.

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WILL GIVE BRAINLY IF QUICK. 40 POINTS!!!!
sdas [7]

Answer:

x = \sqrt{1}

Step-by-step explanation:

(x + 6 )^2 = 49

get rid of the square , by square rooting the 49

x + 6 = \sqrt{49}

x = \sqrt{49} -6

x = \sqrt{1}

\sqrt{49} means + or - hence it could be -7 -6 = -1 ... or  7-6 = 1

therefore the answer is = or -  1

hence in terms of roots .. answer is :

\sqrt{1}

3 0
4 years ago
Read 2 more answers
I new help with number 1 and number 2
Natalka [10]
I hope this helps you

4 0
4 years ago
the length of a rectangle is 2 cm more than 5 times the width. The perimeter 196 cm.Find the width and length
blondinia [14]

w(5)+2+w=196

5w+2+w=196

6w+2=196

6w=194

w=32 1/3

4 0
3 years ago
A programmer wants to display how the shape of a rectangle with a fixed perimeter of 300 inches can be changed by varying the re
stiv31 [10]

If the rectangle has a fixed width of 300, it means that

2(l+w)=300 \iff l+w=150 \iff w=150-l

where w and l are width and length, respetively.

So given the length l, the are would be

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7 0
4 years ago
Find two unit vectors orthogonal to both given vectors. i j k, 4i k
Maurinko [17]
The cross product of two vectors gives a third vector \mathbf v that is orthogonal to the first two.

\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k

Normalize this vector by dividing it by its norm:

\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)

To get another vector orthogonal to the first two, you can just change the sign and use -\mathbf v.
6 0
3 years ago
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