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salantis [7]
3 years ago
11

What is the greatest possible integer value of x for which square root of √x-5 is an imaginary number

Mathematics
2 answers:
Pani-rosa [81]3 years ago
8 0
The greatest of must be less than five .i.e 4
\sqrt{4-5} = \sqrt{-1}
umka21 [38]3 years ago
4 0
The correct answer for this question is 4.

We have to bear in mind that any number  should be less than 5 to make the square root be an imaginary number.
Starting with 4
= square root (4 - 5)
= square root (-1)
= imaginary 

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