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Anna71 [15]
3 years ago
7

One pyruvate molecule will generate _______ molecules of CO2 after completing the citric acid cycle

Biology
2 answers:
Rzqust [24]3 years ago
8 0

Answer:

c) 3

Explanation:

Cellular respiration includes following 3 processes:

1) Glycolysis

2) Citric acid cycle or TCA or Kreb's cycle

3) Electron Transport Chain (ETC)

In glycolysis, a 3 carbon compound known as pyruvate is produced from glucose. Each glucose molecule produces 2 pyruvate molecules. Each pyruvate molecule then enters a complex known as Pyruvate dehydrogenase complex wherein the pyruvate molecule further undergoes oxidative decarboxylation to produce a 2 carbon compound known as Acetyl-CoA.

.

The Acetyl-CoA then enters citric acid cycle or TCA or Kreb's cycle wherein this Acetyl-CoA and oxaloacetate are oxidized to produce CO₂ molecules in eight steps. Each glucose molecule is capable of producing six CO₂ after the completion of citric acid cycle. Since one glucose molecule produces 2 pyruvate molecules then it means <u>a pyruvate molecule will be able to produce three CO₂.</u>

Pavel [41]3 years ago
6 0

Answer:

Option B, 1

Explanation:

Two pyruvate molecules enters into the citric acid cycle and during the stage of pyruvate oxidation , one carboxyl molecules detaches from each pyurvate group thereby forming carbon dioxide and leaving behind a molecule consisting of two carbon for further processes. Hence, in one complete CAC two carbon dioxide molecules are released from two pyruvate molecule. This means that One pyruvate molecule will generate one molecules of CO2 after completing the citric acid cycle

Hence, option B is correct

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List four examples of how you think elderly people living in care facilities can benefit from person centered care
castortr0y [4]

Answer:

1. They can have constant trained medicals around them, which is good because they could have emergencies.

2. They won’t be alone in there houses, but instead have people and life surrounding them.

3. They’ll have people taking care and looking out for them, other than family.

4. They’ll be comfortable, more happy, and more likely to live a happy end to their lives.

Explanation:

6 0
3 years ago
How does the system of classification relate to the diversity of species?
11111nata11111 [884]
The system of classification relates to the diversity of species because the system of classification is how we organize the diversity of species. With out it we would have a hard time trying to determine which animals belong with which group. There would be no order, just chaos of trying to determine animal likeness of one another. 
To cut this answer short, it helps them organize organisms. 

6 0
3 years ago
Can an isolated ecosystem be sustainable?
Rama09 [41]

Answer:

Therefore, an isolated ecosystem,  will only be sustainable if it fulfills the condition of Organizational Sustainability:

Explanation:

6 0
3 years ago
Read 2 more answers
1. What does the electric field strength
antiseptic1488 [7]

Answer:

Option A. magnitude

Explanation:

Electric field is the area around the electric current where its effect is observed. If the lines of electric field are close to each other, it means electric field is stronger and if the lines are far away from each other so it indicates that the electric field is weak. There is inverse relationship between electric field and distance from the charge. If the distance is higher, so the electric field is weak and vice versa.

6 0
3 years ago
If you know that a population is 75% the dominant phenotype and 25% is the recessive phenotype, can you determine approximately
Andreyy89
If dominant allele = p, and recessive allele = q,
and p+q = 1, then:
{(p + q)}^{2}  =  {p}^{2}  + 2pq +  {q}^{2}  \\ where \:  {p}^{2}  \: is \: homozygous \: domin \\  {q}^{2}  \: is \: homozygous \: recessive \\ and \: 2pq = heterozygous
So if 75% have the p, then p^2 = homozygous dominant
{p}^{2}  =  {(.75)}^{2}  = .5625
And if the other 25% have the q, the q^2 = homozygous recessive
{q}^{2}  =  {(.25)}^{2}  = .0625
Now those remaining MUST be the heterozygous, thus 2pq are those:
2pq = 2(.75)(.25) = .375

Therefore homozygous dominant are 56.3% and heterozygous are 37.5%
8 0
3 years ago
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