Answer:

Step-by-step explanation:
Circumference of the column 
Circumference of a circle
Therefore:

Area of a Circle 
Since radius of the cross section of the column =9 meters
Area of the cross section of the column

Answer:
the volume of the sphere is

Step-by-step explanation:
This problem bothers on the mensuration of solid shapes, sphere and cube.
Given data
Volume of cube v = 64 cubic inches
since we are dealing with a cube the height and the radius of the sphere is same as the sides of the cube,
we know that volume of cube is expressed as



![l= \sqrt[3]{64}](https://tex.z-dn.net/?f=l%3D%20%5Csqrt%5B3%5D%7B64%7D)

also diameter d=length l
Diameter d=
Radius r =
=
= 
Height h=
we know that the volume of a sphere is given by

substituting into the formula we have

The area of the square is 81 sq in, and the area of the circule is (3.14)(3 in)^2, or approx 3.14(9) sq in, or approx 28.27 sq in.
Subtract: 81 sq in - 28.27 sq in = approx. 52.73 sq in.
The difference is 52.73 sq in; the square is larger, the circle smaller.
Ricky jogged 6 miles on tuesday and 6 miles on friday
<em><u>Solution:</u></em>
Given that,
Rick jogged the same distance on tuesday and friday
Let "x" be the distance jooged on each tuesday and friday
He also jogged for 8 miles on sunday
Total of 20 miles for the week
Therefore, we frame a equation as,
total distance jogged = miles jogged on tuesday + miles jogged on friday + miles jogged on sunday
20 = x + x + 8
20 = 2x + 8
2x = 20 - 8
2x = 12
x = 6
Thus Ricky jogged 6 miles on tuesday and 6 miles on friday
Answer:
d = 4/c.
Step-by-step explanation:
Inverse variation is : d = k/c where k is a constant.
Here k = 4.