Answer:
The height of a jugglers ball that has been in the air for 1.5 seconds is 6.5 feet
Step-by-step explanation:
we are given height equation as
where
h is the height in feet of a Juggler's ball after t seconds
now, we can plug t=1.5
we can solve for h
So,
The height of a jugglers ball that has been in the air for 1.5 seconds is 6.5 feet
Step-by-step explanation:
Range if third side is in between 10-22
Reason:
<em>For </em><em>the </em><em>lowest </em><em>value </em><em>of </em><em>third </em><em>side </em><em>1</em><em>6</em><em>-</em><em>6</em><em>=</em><em> </em><em>1</em><em>0</em><em> </em>
<em>For </em><em>the </em><em>highest</em><em> </em><em>value</em><em> </em><em>if </em><em>third</em><em> </em><em>side </em><em>1</em><em>6</em><em>+</em><em>6</em><em>=</em><em> </em><em>2</em><em>2</em>
<em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em><em>⚡</em>
Answer:
Step-by-step explanation:
Jmeu eimejrimr
Answer:
The answer to the question is
1.5 hours that is;
When the distance between them is more then 135 miles is after 1.5 hours and they will lose radio contact at 3:30 p.m.
Step-by-step explanation:
We note that
The speed of the military convoy headed north =50 mph
The speed of the convoy headed south = 40 mph
Let t be the time taken for the two convoys to be 135 miles apart
The time taken for the two convoys to be 135 miles apart is given by
50×t miles+ 40×t miles= 135 miles
That is 90×t miles = 135 miles
t = 135/90 = 1.5 hrs
