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Masteriza [31]
3 years ago
6

True or false, there are two solutions to the equation |x-21|= -7

Mathematics
2 answers:
Alex Ar [27]3 years ago
6 0

False, there are no solutions to the equation |x − 21| = −7 because the absolute value cannot be less than 0.

notsponge [240]3 years ago
4 0

Answer:

false

Step-by-step explanation:

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The answer is X = 11 - 3. This is because to calculate the original value of how many books Isabella had, you have to take away the amount purchased from the overall total amount. Therefore, the equation is x = 11-3
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What is formula in your own words?
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A mathematical relationship or a rule mostly expressed in symbols
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If A(1,2), B(5,-4) and (-3,2) are the vertices of a triangle, which statement holds true?
Zigmanuir [339]

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The correct option is A.

<h3>What is a triangle?</h3>

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The sum of all the angles of a triangle is always equal to 180°.

The length of different sides are:

AB = \sqrt{(5-1)^2+(-4-2)^2} = \sqrt{16+36} = \sqrt{52}\rm\ units

BC = \sqrt{(-3-5)^2+(2+4)^2} = \sqrt{64+36} = 10\rm\ units

AC = \sqrt{(2-2)^2+(-3-1)^2} = \sqrt{16} = 4\rm\ units

Since the length of all the sides of the triangle is not equal it is a scalene triangle.

Hence, the correct option is A.

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7 0
1 year ago
Read 2 more answers
The market and Stock J have the following probability distributions:
denis-greek [22]

Answer:

1) E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

2) E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

3) E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

4) E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

Step-by-step explanation:

For this case we have the following distributions given:

Probability  M   J

0.3           14%  22%

0.4           10%    4%

0.3           19%    12%

Part 1

The expected value is given by this formula:

E(X)=\sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

Part 2

E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%

Part 3

We can calculate the second moment first with the following formula:

E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

Sd(M) = \sqrt{13.89}= 3.73

Part 4

We can calculate the second moment first with the following formula:

E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

Sd(M) = \sqrt{55.56}= 7.45

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enyata [817]
Igor: 6 pencils: 1 pack
Elsa: 18 pencils: 3 packs
6 0
3 years ago
Read 2 more answers
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