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Effectus [21]
3 years ago
11

Solve the following equation by transforming it into a perfect square trinomial.

Mathematics
1 answer:
bixtya [17]3 years ago
7 0
X^2 - 14 x  = 15

(x - 7)^2 - 49 = 15

(x-7)^2 = 64

x - 7 = - or  + 8

x = 15  or -1 

Just take half o the coefficient of x and subtract it squared as above.

In general

x^2 + ax = b

(x + a/2)^2 - a^2/4 = b 
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Answer the following ratios <br><br> 55 paise to Rs 1<br> 500ml to 2 liters
AfilCa [17]
55:1

500:2

There ya go!
7 0
3 years ago
Please help these are not easy for me
Pavel [41]

Answer:

12a^2 - 9a + 5

Step-by-step explanation:

(5a^2 - 6a - 4) - (-7a^2 + 3a - 9)

5a^2 + 7a^2 = 12a^2

-6a - 3a = -9a

-4 + 9 = 5

12a^2 - 9a + 5

7 0
3 years ago
Divide using long division. HELP ASAP!!
pav-90 [236]

Answer:

The answer to your question is the first option

Step-by-step explanation:

Write the division

                               7x³  - 7x²   + 6x   +4                        Result

                  x + 1     7x⁴  -  0x³  - 1x²  +  10x  + 15

                             -7x⁴   -  7x³

                               0     -  7x³  - 1x²      

                                       + 7x³ +7x²

                                          0    + 6x² +  10x

                                                - 6x²  -    6x

                                                    0    +   4x  + 15

                                                          -    4x  -   4

                                                                0   + 11            Remainder

Result =  7x³ - 7x² + 6x + 4 + 11 / x + 1

8 0
4 years ago
A circular swimming pool has a radius of 28ft. There is a path all the way around the pool that's 4ft wide. A fence is going to
Natalka [10]

Answer:

Therefore 200.96 ft.of fencing are needed to go around the pool path.

Step-by-step explanation:

Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.

The radius of the outside edge the pool path is

= Radius of the pool + The width of the path

= (28+4) ft

= 32 ft.

To find the length of fencing, we need to find the circumference of outside the pool path.

Here r= 32 ft

The circumference of outside edge of the pool path

=2\pi r

=(2\times 3.14 \times 32) ft

=200.96 ft.

Therefore 200.96 ft.of fencing are needed to go around the pool path.

3 0
4 years ago
The pyramid shown has a square base that is 1212 centimeters on each side. The slant height is 1818 centimeters. What is the sur
S_A_V [24]

Answer : Surface area of pyramid = 4406832 square cm.

Explanation :

Since we have given that

Side of square base = 1212 cm

Slant height of pyramid = 1818 cm

As we know that ,

\text{Surface area of pyramid }=\frac{1}{2}\times perimeter\times \text{ slant height}

\text{ Since, perimeter of square }=4\times side\\=4\times 1212\\=4848 cm

Now,

\text{ Surface area of pyramid }= \frac{1}{2}\times 4848\times 1818\\\\\text{ Surface area of pyramid }=4406832\text{ square cm}

Hence, surface area of pyramid = 4406832 square cm.


5 0
3 years ago
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