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elena-14-01-66 [18.8K]
3 years ago
8

Find the equation of a line that is parallel to the line x equals negative 1x=−1 and contains the point left parenthesis negativ

e 2 comma 1 right parenthesis .
Mathematics
1 answer:
sineoko [7]3 years ago
8 0
The equation of the line is given as y-x=-1

A straight line equation is given in the form y=mx+c where m is the gradient and c is the y-interest.

We need to rearrange y-x=-1 to make y the subject. 
y= x-1 ⇒ from here we can read the gradient and the y-intercept. The gradient, m=1 and c=-1.

<span>A line that is parallel to y=x-1 will have the same gradient, m=1 but different y-intercept. One example of equation of a line that is parallel to y=x-1 is y=x+3


</span>
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Answer:

1

Use the quadratic formula

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac​​

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

2

+

5

−

2

=

0

x^{2}+5x-2=0

x2+5x−2=0

=

1

a={\color{#c92786}{1}}

a=1

=

5

b={\color{#e8710a}{5}}

b=5

=

−

2

c={\color{#129eaf}{-2}}

c=−2

=

−

5

±

5

2

−

4

⋅

1

(

−

2

)

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⋅

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this should help

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