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yuradex [85]
2 years ago
10

(25 points) Which of the following equations matches the graph above?

Mathematics
1 answer:
Dennis_Churaev [7]2 years ago
8 0

Answer:

B.

Step-by-step explanation:

y intercept: 3

Slope: rise 2 run 1 so -2/1 or -2

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Answer:

area = 2604 in²

Step-by-step explanation:

area = L x W

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Use the diagram of the right triangle above and round your answer to the nearest hundredth. If m <br> a. 17.32 m<br> b. 6.93 m<b
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In ΔABC,
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4 0
2 years ago
Jimmy ran at a speed of m miles. how far did he run in t minutes
beks73 [17]

Answer:

(mxt) miles

Step-by-step explanation:

speed = m \: miles \: per \:minute \\ time \:  = t \: minutes \\ speed =  \frac{distance}{time}  \\ m =  \frac{d}{t}  \\ m \times t \:  = d \\ d = (m \times t)miles

hope that this is helpful.

8 0
2 years ago
It has a time to failure distribution which is normal with a mean of 35,000 vehicle miles and a standard deviation of 7,000 vehi
Triss [41]

Answer:

The designed life should be of 21,840 vehicle miles.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles.

This means that \mu = 35000, \sigma = 7000

Find its designed life if a .97 reliability is desired.

The designed life should be the 100 - 97 = 3rd percentile(we want only 3% of the vehicles to fail within this time), which is X when Z has a p-value of 0.03, so X when Z = -1.88.

Z = \frac{X - \mu}{\sigma}

-1.88 = \frac{X - 35000}{7000}

X - 35000 = -1.88*7000

X = 21840

The designed life should be of 21,840 vehicle miles.

3 0
2 years ago
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