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Neporo4naja [7]

2 years ago

5

I need help solving x^2-2=7 by factoring

1 answer:

bonufazy [111]2 years ago

4 0

x^2-2=7

Subtract 7 from both sides

x^2-2-7=7-7

x^2-9=0

x^2-3^2=0

Using a^2-b^2=(a+b)(a-b)

Where a=x and b=3

(x-3)(x+3)

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Masteriza [31]

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Add "g" on both sides

$\frac{x}{5} = a +g$

Multiply 5 on both sides to get x by itself

x = 5(a + g)

x = 5a + 5g

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Subtract 1 on both sides

a - 1 = 3n

Divide 3 on both sides to get n by itself

$\frac{a - 1}{3} = \frac{a}{3} -\frac{1}{3}$ = n

21. M = T - R

Add "R" on both sides to get "T" by itself

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Subtract "5p" on both sides

9c = p - 5p

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27. 4y + 3x = 5

Subtract "4y" on both sides

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Divide 3 on both sides to get "x" by itself

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Create an equivalent expression using the drop downs below 4(32 – 4).

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2 years ago

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Anon25 [30]

Answer:

$f(x - 4) = x^2 - 6x+ 8$

Step-by-step explanation:

Given

$f(x) = x^2 + 2x$

Required

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Substitute x - 4 for x

$f(x - 4) = (x- 4)^2 + 2(x - 4)$

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$f(x - 4) = x^2 - 8x + 16 + 2x - 8$

Collect like terms

$f(x - 4) = x^2 - 8x + 2x+ 16 - 8$

$f(x - 4) = x^2 - 6x+ 8$

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2 years ago