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3 years ago

I need help solving x^2-2=7 by factoring

Mathematics

1 answer:

bonufazy [111]3 years ago

4 0

x^2-2=7

Subtract 7 from both sides

x^2-2-7=7-7

x^2-9=0

x^2-3^2=0

Using a^2-b^2=(a+b)(a-b)

Where a=x and b=3

(x-3)(x+3)

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Rudik [331]

Answer:

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3 years ago

The number 6545 can be written as a product of a pair of positive two digit integers. What are these two integers?

weqwewe [10]

Answer:

77 and 85

Step-by-step explanation:

Since the number 6545 ends in a 5, we can assume that one of the two digit numbers ends in a 5. I tried 55, 65, 75, and 85, and I just divided 6545 by those numbers until I got a two-digit positive integer as my answer,

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Therefore, the answer is 85 and 77.

I hope this helps!

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3 years ago

G(x) = 4х+1

DanielleElmas [232]

I believe it’s 13

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3 years ago

What is the factored form of this expression? 27m^3 +125n^3

ddd [48]

Answer:

$\left(3m+5n\right)\left(9m^2-15mn+25n^2\right)$

Step-by-step explanation:

$27m^3+125n^3=\left(3m\right)^3+\left(5n\right)^3$

Apply sum of cubes formula: $x^3+y^3=\left(x+y\right)\left(x^2-xy+y^2\right)$

$\left(3m\right)^3+\left(5n\right)^3=\left(3m+5n\right)\left(3^2m^2-3m\times 5n+5^2n^2\right)$

$\left(3m+5n\right)\left(9m^2-15mn+25n^2\right)$

5 0

3 years ago

Read 2 more answers

Can someone plz help me with this

slava [35]

Answer:

Step-by-step explanation:

2a. f(-3) = (-3)^2-4(-3)+6 = 9+12+6 = 27

2b. f(-2) = 3(-2)^2-(-2)^3 -2 +1 = 3(4) - (-8) -2 +1

= 12+8-1 = 19

8 0

2 years ago