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saveliy_v [14]
3 years ago
6

you enclose a field using sections of fence with length of 15,20 and 25 meters estimate the area of the field

Mathematics
1 answer:
bixtya [17]3 years ago
8 0

Answer:

150 square meters

Step-by-step explanation:

Assuming that this field is triangular, we can multiply the two shortest sides together, and then divide by 2, because that is the formula for the area of a right triangle.

So 15 times 20 is 300

300 divided by 2 is 150

So we can estimate the area to be 150 square meters.

(Upon solving further, we realize that this is a right triangle, so our initial estimation is the exact area)

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On Monday a shop receives $60.30 by selling bottles of water at 45 cents each
True [87]

Answer:

134 bottles

Step-by-step explanation:

For this, I set up a proportion :

60.30/x = 0.45/1

60.30(1) = 0.45x

60.30/0.45 = 0.45x/0.45

x = 134 :)

5 0
2 years ago
Read 2 more answers
Simplify -4 + (-3) + 6
Sedaia [141]
Start off with: -4 + (-3) + 6

First of all, when there is a, + sign and a - sign next to each other, the - side wins.
E.g. 1 +- 3 = 1 - 3

So, apply this to our one:
-4 -3 +6

From there you solve, you can do this using the number line method or whatever you are into:
=-7 + 6
=-1
The answer is -1




3 0
2 years ago
How do you get rid of a power in an equation?
sergij07 [2.7K]
Usually, to get rid of a power in an equation, you square root whatever the power is attached to.
3 0
3 years ago
MARKING AS BRAINLIEST!! (Geometry)
lana [24]

Answer:

x = 15.49

Step-by-step explanation:

As you can see this is a right-angled triangle due to the right angle symbol, we can use Pythagorean theory to find the unknown length:

a^2 + b^2 = c^2

In this case, we know C and B but not A so:

a^2 = c^2 - b^2

Now plug the values in:

a^2 = 16^2 - 4^2

a^2 = 256 - 16

a^2 = 240

Square root the answer to get A:

a = \sqrt{240}

a = 15.49

x = 15.49

Hope this helps!

5 0
2 years ago
Draw a graph for the situation.
n200080 [17]
It will be a discrete graph, where there is no dependant nor independent variables, they are not related by any means.

Hope this helps.

6 0
3 years ago
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