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artcher [175]
3 years ago
12

77 is written as the product of two prime numbers 7 × 11. Can 702 be written as the product of two prime numbers? If not, why? W

hat about 703?​
Mathematics
1 answer:
kari74 [83]3 years ago
6 0

Answer:

702 can't be written as the product of 2 prime numbers because if you divide 702 by 2 then you get 351 and that is not a prime number. Therefore, 702 is a prime number.

The prime factorization of 703 is 19 × 37. Since it has a total of 2 prime factors, 703 is a composite number.

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Solve this equation using order and operations:
exis [7]

Answer:

(1680)

Step-by-step explanation:

Simplify the following:

3 (10 (6 + 2 (22 + 8) - 10))

| 1 |  

| 2 | 2

+ | | 8

| 3 | 0:

3 (10 (6 + 2×30 - 10))

2×30 = 60:

3 (10 (6 + 60 - 10))

6 + 60 = 66:

3 (10 66 - 10)

| 6 | 6

- | 1 | 0

| 5 | 6:

3 (10×56)

10×56 = 560:

3 (560)

3 (560) = (3×560):

(3×560)

3×560 = 1680:

Answer: (1680)

5 0
3 years ago
Let f be a real-valued function defined on [0,∞), with the properties: f is
USPshnik [31]

im not sure this is right

g'(x) = 6b(-5x + 1)^5 (-5)

g'(x) = -30b(-5x +1)^5

g''(x) = -30b(5)(-5x + 1)^4 (-5)

g''(x) = 750b (-5x +1)^4

g(x) = b(−5x + 1)6 − a

when

g(-x) = b(5x +1)6 - a

g'(x) = -30b(-5x +1)^5 = 0

-5x +1 = 0

x = 15

8 0
2 years ago
Thirty percent of the students at a local high school face a disciplinary action of some kind before they graduate. Of those "fe
inna [77]

Answer:

Not independent

Step-by-step explanation:

For two events to be independent, they must not effect each other. For two independent events, changes in one of the event do not cause any change on the other event.

To explain it in terms of probability, let's first define and calculate the probabilities:

P(F) : Probability of facing felony

P(C) : Probability of going to college

P(F ∩ C) : Probability of facing felony and going to college

P(F° ∩ C): Probability of not facing a felony and going to college

Assume we have 100 students:

Faced felony = 0.3 * 100 = 30

Faced felony and go college = 30 * 0.4 = 12

Not faced felony = 0.7 * 100 = 70

Not faced felony and go college = 0.6 * 70 = 42

Total of going to college = 12 + 42 = 54

So P(C) = 54 / 100 = 0.54

If P(F)*P(C) = P(F ∩ C), then these two events are independent. If not, they are not independent.

Let's calculate the probabilities:

As given in the question, 30% of students face felony so P(F) = 0.3

P(C) = P(C ∩ F) + P(C ∩ F°) = 0.12 + 0.42 = 0.54

P(F) = 0.3

P(F ∩ C) = 0.12

P(F)*P(C) = 0.3 * 0.54 = 0.162 which ic not equal to P(F ∩ C). Therefore, these events are not independent.

5 0
3 years ago
Yz + 3wx can y you please help me​
MissTica

Answer:

3wxyz

Step-by-step explanation:

just add the variables

4 0
3 years ago
The binomial 5x – 4 is a factor of 10x2 – 23x + 12. What is the other factor?
SVETLANKA909090 [29]
Method\ 1^o\\10x^2-23x+12=(5x-4)(ax+b)\\\\10x^2-23x+12=5ax^2+5bx-4ax-4b\\\\10x^2-23x+12=5ax^2+(5b-4a)x-4b\\\\therefore\\\\  \begin{array}{ccc}(1)\\(2)\\(3)\end{array}\left\{\begin{array}{ccc}5a=10\\5b-4a=-23\\-4b=12\end{array}\right\\\\(1)\ divide\ both\ sides\ by\ 5\to a=2\\(3)\ divide\ both\ sides\ by\ (-4)\to b=-3\\check\\subtitute\ the\ values\ of\ "a"\ and\ "b"\ to\ (2):\\5\cdot(-3)-4\cdot2=-15-8=-23\ /correct/\\\\Answer:\boxed{2x-3}


Method\ 2^o\\10x^2-23x+12=10x^2-8x-15x+12\\=2x\cdot5x-2x\cdot4-3\cdot5x-3\cdot(-4)\\=2x(5x-4)-3(5x-4)=(5x-4)\boxed{(2x-3)}
6 0
3 years ago
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