Answer:
import java.util.Scanner;
class Main {
public static int calcSeries(int n) {
int sum = 0;
for(int i=10; i>=n; i--) {
sum += i;
}
return sum;
}
public static void main(String[] args) {
Scanner reader = new Scanner(System.in);
int n = 0;
do {
System.out.print("Enter n: ");
n = reader.nextInt();
if (n >= 10) {
System.out.println("Please enter a value lower than 10.");
}
} while (n >= 10);
reader.close();
System.out.printf("sum: %d\n", calcSeries(n));
}
}
Answer:
FALSE
Explanation:
The blanket purchase agreement (BPA) can not serves as an agreement that documents the technical requirements of interconnected assets but the Interconnection service agreement (ISA).
Answer:
The required formula to get the value of the cell K6 i.e., total cost of the rental based on the daily rate, cost of gas, amount of discount, and number of days rented can be given as follows:
K6 =E6*G6*(1-H6)-J6
Explanation:
In the above formula, the value of the cell E6 (#Days rented) is being multiplied with the cell G6 (Daily rate), amount of discount (H6) subtracted from 1 and subtract the cell value J6 (Cost of gas) from the resulted value of the expression E6*G6*(1-H6).
Copy the above formula to the range K7:K32 to fill all the values. The resulted excel sheet will be shown as follows:
Answer:
The correct answer to the following question will be "n logn".
Explanation:
- Time Complexity should be the same as the whole last particular instance, just the log base keeps changing with three.
- Throughout the circumstance of separating 2 arrays, we want one correlation. however, for splitting between 3-way arrays, will require 2 comparisons to sort.
- However, after breaking the array into 3, we can lower the number of transfers by growing the comparison. So the time complexity would then persist the same, but the log should get base 3 as we've classified into different parts.
So the time complexity will be:
⇒ 
⇒ 