Answer:
0.906
Explanation:
Let g = 9.81 m/s2. We can calculate the rate of change in potential energy when m = 201kg of water is falling down a distance of h = 131m per second
So the efficiency of the water turbine is the ratio of output power over input power:
1.)Multi-cellular
2.)Organism
3.)Cells
4.)Uni-cellular
5.)Homeostasis
6.)Reproduction
7.)Response
8.)Stimulus
9.)Energy
10.)Photosynthesis
11.)Plants
12.)Glucose
13.)Reproduction
I pretty sure these are correct,
Hope this helps
Answer:
The plant root is an example of an organ.
Plant consists of many different organs, which include leaves, stem, reproductive organs, and roots. All the organs play a different role in the plant.
Answer:
V = 23.6062 cm³
General Formulas and Concepts:
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Gas Laws</u>
Explanation:
<u>Step 1: Define</u>
Mass <em>m</em> = 455.6 g
Density <em>D</em> = 19.3 g/cm³
<u>Step 2: Solve for </u><em><u>V</u></em>
- Set up: 19.3 g/cm³ = 455.6 g / V
- Isolate <em>V</em>: V = 23.6062 cm³
Answer:
0.342g of octane
Explanation:
First let us generate a balanced equation for the reaction this is illustrated below:
2C8H18 + 25O2 —> 16CO2 + 18H20
Next, we'll calculate the molar mass and masses of C8H18 and O2
Molar Mass of C8H18 = (12x8) + (18x1 ) = 96 + 18 = 114g/mol
Mass of C8H18 from the balanced equation = 2 x 114 = 228g
Molar Mass of O2 = 16 x 2 = 32g/mol
Mass of O2 from the balanced equation = 25 x 32 = 800g
From the equation,
228g of octane(C8H18) were consumed by 800g of O2.
Therefore, Xg of octane will be consumed by 1.2g of O2 i.e
Xg of octane = (228 x 1.2)/800 = 0.342g
Therefore 0.342g of octane will be consumed
