Answer:
1.414 Moles
Solution:
Data Given:
Mass of MgS₂O₃ = 193 g
M.Mass of MgS₂O₃ = 136.43 g.mol⁻¹
Moles = ?
Formula Used:
Moles = Mass ÷ M.Mass
Putting values,
Moles = 193 g ÷ 136.43 g.mol⁻¹
Moles = 1.414 mol
The formula for density is:
D = m/v
We can use the formula to figure out the mass because we already know two of the three values (we are given the density and volume), so we only have to solve for <em>m. </em>If we plug our given values into the formula, we get:
2.70 = m / 264
Now, all we need to do is solve for <em>m</em>. The goal is to get <em>m</em> on one side of the equation, and all we have to do is multiply each side of the equation by 264:
264 × 2.70 = (m÷264) × 264
264 × 2.70 = m
m = 712.8
The mass of the piece of aluminum is 712.8 grams.
Answer:
Size of the nucleus of an atom is very small as compared to the size of the atom.
According to Rutherford gold foil experiment, nucleus is very small in size as compared to the size of the atom as a whole. Nucleus is very hard, dense and positively charged which consists of protons and neutrons.
Explanation:
element is made up of only one type of atoms.
it is pure form of matter
example hydrogen, oxygen, carbon etc
