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Ber [7]
4 years ago
9

What is the molecular formula of a compound with the empirical formula HSO4 and a formula mass of 194.13 amu?

Chemistry
1 answer:
nadya68 [22]4 years ago
4 0

Answer:

Molecular formula =  H₂S₂O₈

Explanation:

Given data:

Empirical formula = HSO₄

Formula mass = 194.13 amu

Molecular mass = ?

Solution:

Molecular formula = n × empirical formula

n = molar mass of the compound / empirical formula mass

Empirical formula mass = 1.008 + 32.065 + 16× 4

Empirical formula mass = 97.073

n = 194.13 / 97.073

n= 2

Molecular formula = n × empirical formula

Molecular formula = 2  (HSO₄)

Molecular formula =  H₂S₂O₈

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It allows you to determine the relation between the reactants and the products.

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How do water particles move in a wave? A. They move forward with the wave. B. They move in a circular motion. C. They move up an
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Sorry if I'm wrong but I think that it is B. 
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3 years ago
If 15 grams of Carbon dioxide is produced in a chemical reaction, how many grams of Carbon must be consumed in the reaction if w
irinina [24]

Answer:

4.13 g

Explanation:

Data Given:

Amount of CO₂ Produced = 15 g

Amount of Oxygen = 11 g

Amount of Carbon used = ?

Solution:

Suppose Carbon dioxide (CO₂) is formed by the reaction of carbon and oxygen then the reaction will be as below

                            C   +   O₂    -------------> CO₂

                          1 mol    1 mol                  1 mol

we come to know from the above reaction that

1 mole of carbon react with 1 mole of oxygen to produce 1 mol of carbon dioxide.

molar mass of C = 12 g/mol

molar mass of O₂ = 32 g/mol

molar mass of CO₂ = 12 + 2(16) = 44 g/mol

if we represent mole in grams then

           C               +                        O₂                     ------------->        CO                 1 mol (12 g/mol)                      1 mol (32 g/mol)                      1 mol (44 g/mol)

                   

              C   +   O₂    -------------> CO₂

            12 g       32 g                   44 g

So,

we come to know that 32 g of Oxygen combine with 12 g  of oxygen produce 44 g CO₂

So now how much of Carbon will be combine with 11 g of oxygen

apply unity formula

                32 g of  O₂ ≅ 12 g of  C

                  11 g of O₂  ≅  g of  C

by doing cross multiplication

           g of C = 12 g x 11 g / 32 g

           g of C = 132 g / 32 g

           g of C = 4.13 g

So,

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

to check this answer

we use the above information

                     12 g of  C ≅ 44 g of CO₂

                     4.13 g of C ≅  g of  CO₂

by doing cross multiplication

                    g of  CO₂ = 44 g x 4.13 g / 12 g

                    g of CO₂ = 15g

So it is confirmed that

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

4 0
3 years ago
Sodium carbonate, Na2CO3(s), can be prepared by heating sodium bicarbonate, NaHCO3(s). 2 NaHCO3(s) Na2CO3(s) + CO2(g) + H2O(g) K
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Answer:

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Explanation:

Step 1: Data given

Kp = 0.23

Step 2: The balanced equation

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Step 3: Calculate the pressure of CO2

Kp = (p(CO2))*(p(H2O))

For 1 mol CO2 we have 1 mol H2O

x = p(CO2) = p(H2O)

Kp = 0.23 = x*x

x = √0.23

x = 0.48

pCO2 = x atm = 0.48 atm

The pressure of CO2 = 0.48 atm

5 0
3 years ago
4) Complete the following statement: Different elements...
Arada [10]
Have a different number of protons
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