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2 years ago

If x can be any number, how many solutions are there for the equation?

Mathematics

2 answers:

VARVARA [1.3K]2 years ago

5 0

C. There are many solutions
4(5)-1=19
4(10)-1=39

lidiya [134]2 years ago

5 0

I agree...C is the answer. Anytime you put in a value for X, you get a different Y answer, so yes, there are many answers. The other answer gives you two examples using x = 5 and x = 10. You could also substitute any other number for x and get a different y answer; an infinite number of x's and y's actually.

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A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an

Nataly [62]

Answer:

The distance between the walls is 70 m.

Step-by-step explanation:

Given: A source of laser light is at point A on the ground between two parallel walls BE and CD . The walls are perpendicular to the ground that is

BE ⊥ ED and CD ⊥ ED

AB is a ray of light which strikes the wall on the left at point B which is 30 meters above the ground. that is BE = 30 m

AC is a ray of light which strikes the wall on the right at point C. The length of AC = 80 meters.

The ray AB makes an angle of 45 degrees with the ground that is m∠BAE = 45°

The ray AC makes an angle of 60 degrees with the ground that is m∠CAD = 60°

As shown is figure attached below.

WE have to find the distance between the walls that is Length of ED

Length of ED = EA + AD

Consider the Δ AEB,

Using trigonometric ratio,

$\tan\theta=\frac{perpendicular}{base}$

Here $\theta=45^{\circ}$ , perpendicular = 30 m and base we can find.

thus,

$\tan 45^{\circ}=\frac{30}{EA}$

We know $\tan 45^{\circ}=1$

thus, EA = 30 m

Consider the Δ AEB,

Using trigonometric ratio,

$\cos\theta=\frac{base}{hypotenuse}$

Here $\theta=60^{\circ}$ , hypotenuse = 80 m and base we can find.

thus, $\cos 60^{\circ}=\frac{base}{80}$

We know, $\cos 60^{\circ}=\frac{1}{2}$

thus, Base = 40 m

AD = 40 m

Thus, the distance between the walls that is the length of ED = 30 + 40 = 70 m

4 0

3 years ago

A special box designed to hold an antique artifact is shaped like a triangular prism. The surface area of the box is 421.2 squar

Oksanka [162]

The area of the base is:
A = root ((s-a) * (s-b) * (s-c) * (s))
Where,
a, b, c: sides of the triangle
s = (a + b + c) / 2
We have then:
s = (9 + 9 + 9) / 2
s = 13.5
A = root ((13.5-9) * (13.5-9) * (13.5-9) * (13.5))
A = 35.07
Then, the surface area of the prism is:
S.A = 2 * A + 9h + 9h + 9h
Where,
h: height of the prism:
Substituting values:
421.2 = 2 * (35.07) + 9h + 9h + 9h
Clearing h:
27h = (421.2 - 2 * (35.07))
h = (421.2 - 2 * (35.07)) / (27)
h = 13
Answer:
the height of the box is:
h = 13 inches

8 0

3 years ago

Is – 7 a solution to the equation 8 {1/4x +3/4} -3 = 17

I am Lyosha [343]

Answer:

Step-by-step explanation:

Start by using the distributive property to simplify 8(1/4x+3/4):

8•1/4x=2x

8•3/4=6

The equation now reads: 2x+6-3=17. Subtract 3 from six and you get 2x+3=17.

You can now proceed to answer this like any two step linear equation.

2x+3=17