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3 years ago

9

What is the answer to this?

1 answer:

rodikova [14]3 years ago

3 0

Answer:

tkae j ad by f then subtracr the u then add the c then multply k then say u

Step-by-step explanation:

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X^2-8x+16 divided by ax-4x numerator

Vedmedyk [2.9K]

Answer:

Given:

1). $x^2-8x+16$ divided by $x-4$

⇒ $\frac{x^2-8x+16}{x-4}$

⇒ $\frac{x^2-2\times x\times 4+4^2}{x-4}$

By factorising numerator by using identity, $(a-b)^2=a^2-2\times a \times b +b^2$

⇒ $\frac{(x-4)^2}{x-4}$

⇒ $\frac{(x-4)\times(x-4)}{x-4}$

⇒ $x-4$ <u> {Answer}</u>

2). $3x^2y$ divided by $6xy^2$

⇒ $\frac{3x^2y}{6xy^2}$

⇒ $\frac{3\times x\times x\times y}{6\times x\times y\times y}$

⇒ <u> $\frac{x}{2y}$ </u> <u>{ Answer}</u>

4 0

3 years ago

Erica had 6 coins in her coin collection. she goes to a coin show and buys some coins. how many dose she have now?

rewona [7]

It doesnt say how many she buys at the coin show so we dont know but its going to be more than 6

8 0

3 years ago

Read 2 more answers

Question 2. I have another question on my feed. Please help me solve!!!!

Maru [420]

Answer:

A' (11, 4), B' (-10, -6), C' (7, -9)

Step-by-step explanation:

Since you are reflecting over the y-axis, you take the opposite of the x value. So if the x is positive, make it negative. If the x is negative, make it positive. The y coordinate stays the same.

4 0

3 years ago

Given that ΔPQR is similar to ΔPTS, which statement MUST be true? A) m∠PST = m∠QPR B) m∠TPS = m∠RPQ C) m∠SPT = m∠PTS D) m∠PRQ =

galina1969 [7]

Answer:

The correct option is B.

Step-by-step explanation:

Two triangle are similar if their corresponding sides are in the same proportion or the corresponding angles are same.

It is given that the ΔPQR is similar to ΔPTS. It means all corresponding angles are same.

$\angle R=\angle S$

$\angle Q=\angle T$

$\angle P=\angle P$

Angle P can be defined as

$\angle QPR=\angle TPS$

$\angle RPQ=\angle TPS$

Therefore option B is correct.

$\angle PST\neq\angle QPR$

$\angle SPT\neq\angle PTS$

$\angle PRQ\neq\angle PTS$

Therefore option A, C and D are incorrect.

7 0

3 years ago

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What is the trigonometric derivative of Y=2sinx-tanx

Alchen [17]

$\bf y=2sin(x)-tan(x)\implies \cfrac{dy}{dx}=2cos(x)-sec^2(x)$

7 0

3 years ago