Find the mean,median,range of 6 6,8,5,4,6,4,3,8,4

2 answers:

8 0

The numbers in order are
3, 4, 4, 4, 5, 6, 6, 6, 8

The median is the number in the middle, which is 5.
The range is the largest number minus the smallest number, 8 - 3 = 5
The mean is the sum of all the numbers divided by how many number are the in the list, 3 + 4 + 4 + 4 + 5 + 6 + 6 + 6 + 8 = 46, 46/9 = 5.11

Natasha_Volkova [10]3 years ago

4 0

Mean is 5.4
You find this by adding all the numbers together and dividing by how many numbers there are.

Median is 5.5
This is found by putting the numbers in order from least to greatest. After that, you can cross out a number from the left and then the right, repeating the process until you get tot eh middle number. If there are two numbers in the middle, add them together and divide by two.

Range is 5
To find this you subtract the biggest number by the smallest number.

If you would like me to specify on anything, just ask and I will respond when I can.

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A consensus forecastis the average of a large number of individual analysts’ forecasts. Suppose the individual forecasts fora pa

Crank

Answer:

a) $P(X\geq 3.5)=P(\frac{X-\mu}{\sigma}\geq \frac{3.5-\mu}{\sigma})=P(Z\geq \frac{3.5-5.0}{1.2})=P(Z\geq -1.25)$

And we can find this probability using the z table or excel

$P(Z \geq$

b) $P(X\leq 6.0)=P(\frac{X-\mu}{\sigma}\leq \frac{6.0-\mu}{\sigma})=P(Z\leq \frac{6.0-5.0}{1.2})=P(Z\leq 0.833)$

And we can find this probability using the z table or excel:

$P(Z \leq$

c) $P(3.5$

And we can find this probability on this way:

$P(-1.25$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(-1.25$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the interest rate of a population, and for this case we know the distribution for X is given by:

$X \sim N(5.0,1.2)$