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asambeis [7]
2 years ago
13

815 gal/h = how many qt /s

Mathematics
1 answer:
aev [14]2 years ago
6 0
.91qt/s   ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍      ‍   
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I need this answer asap
antoniya [11.8K]

Answer:

240

Step-by-step explanation:

5 0
3 years ago
Find the volume of the following solid. The solid between the cylinder ​f(x,y)equals=e Superscript negative xe−x and the region
PilotLPTM [1.2K]

It is hard to comprehend your question. As far as I understand:

f(x,y) = e^(-x)

Find the volume over region R = {(x,y): 0<=x<=ln(6), -6<=y <= 6}.

That is all I understood. It would be easier to understand with a picture or some kind of visual aid.

Anyways, to find the volume between the surface and your rectangular region R, we must evaluate a double integral of f on the region R.

\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy

Now evaluate,

\int_{0}^{ln(6)}e^{-x}dx

which evaluates to,  5/6 if I did the math correct. Correct me if I am wrong.

Now integrate this w.r.t. y:

\int_{-6}^{6}\frac{5}{6}dy = 10

So,

\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy = 10

7 0
3 years ago
How do you simplify cscx*secx-tanx?
kenny6666 [7]
Csc x · sec x - tan x = 
= 1 / sin x · 1 / cos x - sin x / cos x = 
= 1 / sinx cos x - sin² x / sin x cos x = 
= ( 1 - sin² x ) / (sin x cos x) =
=  cos² x / ( sin x cos x ) = 
= cos x / sin x = cot x 
5 0
3 years ago
Find the unknown angle measures
Usimov [2.4K]

Answer:

Step-by-step explanation:

ok so this is a vetical angle. so they are equal to 180. so if 1 measurement is found the other is the difference of 180 and that angle measeurement.

so y is the same as 110

and 180 - 110 is 70, so x and z are equal to 70.

i hope this helped you :)

8 0
3 years ago
Read 2 more answers
10f – 6 – 10f = -8(-2f - 10) + 10
netineya [11]

Answer:

f= -6    i think

8 0
2 years ago
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