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BartSMP [9]
3 years ago
5

What is the Difference between 8 and -4

Mathematics
2 answers:
pav-90 [236]3 years ago
8 0

Answer:

One is postive and the other is negative but both are integers and whole numbers

Step-by-step explanation:

Alex777 [14]3 years ago
7 0

Answer:

12

Step-by-step explanation:

the difference between 8 and -4 is 8-(-4).

Since there are two negative signs for 4, - times - is positive, it is the sum of 8+4.

8+4=12

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A coin is tossed and a number cube is rolled. What is the probability that the coin shows heads and the number cube shows 5? a.
Inessa [10]

Answer:

1/12

Step-by-step explanation:

P( coin = heads) = number of heads / total = 1/2

P( cube = 5) = number of 5's / total =1/6

P( heads, 5) =1/2 * 1/6 = 1/12

8 0
3 years ago
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A chair’s regular price is $349. It is on clearance for 30% off, and a customer uses a
Hunter-Best [27]

Answer:

$207.66

Step-by-step explanation:

349x.7=244.3

244.3x.85=207.665

Rounded to the nearest 100th

207.66

7 0
3 years ago
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Value of Pq- qp if p=3 and q = -1?. 1?:)​
aleksklad [387]

Answer:

0 is the answer

7 0
3 years ago
Oliver was counting his spare change. He had ten dimes and two quarter. How many times as many dimes does Oliver have than quart
zalisa [80]
1 quarter = 25 cents (he has 2 therefore its 50 cents)
10 dimes = 100 cents = 1 dollar
Oliver has twice as many dimes than he does quarters because 100 divided by 50 = 2. Hope this helps!
7 0
3 years ago
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Construct a quadratic polynomial whose zeroes are negatives of the zeroes of the
sp2606 [1]

Given:

The given quadratic polynomial is :

x^2-x-12

To find:

The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.

Solution:

We have,

x^2-x-12

Equate the polynomial with 0 to find the zeroes.

x^2-x-12=0

Splitting the middle term, we get

x^2-4x+3x-12=0

x(x-4)+3(x-4)=0

(x+3)(x-4)=0

x=-3,4

The zeroes of the given polynomial are -3 and 4.

The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.

A quadratic polynomial is defined as:

x^2-(\text{Sum of zeroes})x+\text{Product of zeroes}

x^2-(3+(-4))x+(3)(-4)

x^2-(-1)x+(-12)

x^2+x-12

Therefore, the required polynomial is x^2+x-12.

4 0
3 years ago
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