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Finger [1]
2 years ago
7

Find the distance between the points (4,-2), (4,-5)

Mathematics
1 answer:
kiruha [24]2 years ago
6 0

\text{Given that,}\\\\(x_1,y_1) = (4,-2)~~ \text{and}~~  (x_2 ,y_2) = (4,-5)\\\\\text{Distance} = \sqrt{(x_2-x_1)^2 + (y_2 -y_1)^2}\\\\~~~~~~~~~~~~=\sqrt{(4-4)^2 + (-5+2)^2}\\\\~~~~~~~~~~~~=\sqrt{0^2+(-3)^2}\\\\~~~~~~~~~~~~=\sqrt{0+9}\\\\~~~~~~~~~~~~=\sqrt 9\\\\~~~~~~~~~~~~=3

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The number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3

<h3>How to determine the number of real zeros?</h3>

The equation of the function is given as:

f(x) = x^3 + 4x^2 + x - 6

Expand the function

f(x) = x^3 + 5x^2 - x^2 + 6x - 5x - 6

Reorder the terms

f(x) = x^3 + 5x^2 + 6x - x^2 - 5x - 6

Factor the expression

f(x) = x(x^2 + 5x + 6) -1(x^2 + 5x + 6)

Factor out x -1

f(x) = (x^2 + 5x + 6)(x -1)

Expand

f(x) = (x^2 + 3x + 2x + 6)(x -1)

Factorize

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Factor out x + 2

f(x) = (x + 3)(x + 2)(x- 1)

The function has been completely factored and it has 3 linear factors

Hence, the number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3

Read more about functions at:

brainly.com/question/7784687

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