3 years ago

Find the area of the shape shown below.

Mathematics

1 answer:

Helga [31]3 years ago

7 0

Answer:

Small triangle: A = 2

Medium Triangle: A = 6

Large triangle: A = 20

Square: A = 4

total area: 32

I got the same as the other person

Step-by-step explanation:

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Answer:

answer is a

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

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Aneli [31]

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3 years ago

Which angle has a sine of -1/2 and a cosine of -√3/2

Sergeeva-Olga [200]

$\sin x=-\dfrac{1}{2} < 0\\\\\cos x=-\dfrac{\sqrt3}{2} < 0\\\\therefore\ x\in(180^o;\ 270^o)$

$\text{We know:}\ \tan x=\dfrac{\sin x}{\cos x}\\\\\text{therefore:}\ \tan x=\dfrac{-\frac{1}{2}}{-\frac{\sqrt3}{2}}=\dfrac{1}{2}\cdot\dfrac{2}{\sqrt3}=\dfrac{1}{\sqrt3}\cdot\dfrac{\sqrt3}{\sqrt3}=\dfrac{\sqrt3}{3}$

$\tan x=\dfrac{\sqrt3}{3}\Rightarrow x=30^o+180^o\cdot k;\ k\in\mathbb{Z}$

$x\in(180^o;\ 270^o)\ therefore\ \boxed{x=30^o+180^o=210^o}$

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