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Sloan [31]
3 years ago
6

Find the area of the shape shown below.

Mathematics
1 answer:
Helga [31]3 years ago
7 0

Answer:

Small triangle: A = 2

Medium Triangle: A = 6

Large triangle: A = 20

Square: A = 4

total area: 32

I got the same as the other person

Step-by-step explanation:

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What is the measure of angle 4??? please help asap!!!
ArbitrLikvidat [17]
<h3>Answer: 80 degrees</h3>

===========================================================

Explanation:

Angle 3 and the 100 degree angle are corresponding angles. They are both in the southeast quadrant of their four-corner angle configuration. Assuming the lines that look horizontal are parallel, this would mean angle 3 is 100 degrees. Recall that corresponding angles are congruent when we have parallel lines.

Once we know that angle 3 = 100, we will use this to find angle 4.

Angles 3 and 4 add to 180. They form a straight angle or straight line.

(angle3)+(angle4) = 180

(100) + (angle4) = 180

angle4 = 180-100

angle4 = 80 degrees

7 0
2 years ago
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x^2+1/2x+1/16=4/9 Factor the perfect-square trinomial on the left side of the equation. (x + )² = 4/9
Nezavi [6.7K]
The missing number is the square-root of the constant term on the left-hand-side, which equals sqrt(1/16)=1/sqrt(16)=1/4.
Check:
(x+1/4)^2=x^2+2*(1/4)x+(1/4)^2=x^2+x/2+1/16.   ok

Answer: x= 1/4
5 0
3 years ago
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Find the area of a triangle with base of 10 inches and altitude to the base of 16 inches.
Ostrovityanka [42]
(10*16)/2
160/2=80
The area is 80.

4 0
3 years ago
Y=-x^2+2x+10<br> y=x+2<br><br> Substitution <br> Please show your work<br> Need ASAP
erik [133]

Answer:

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

Step-by-step explanation:

we have

y=-x^{2} +2x+10 ----> equation A

y=x+2 ----> equation B

Solve the system by substitution

substitute equation B in equation A

x+2=-x^{2} +2x+10

solve for x

-x^{2} +2x+10-x-2=0

-x^{2} +x+8=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-x^{2} +x+8=0

so

a=-1\\b=1\\c=8

substitute in the formula

x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}

x=\frac{-1\pm\sqrt{33}} {-2}

x=\frac{-1+\sqrt{33}} {-2}  -----> x=\frac{1-\sqrt{33}} {2}  

x=\frac{-1-\sqrt{33}} {-2}  -----> x=\frac{1+\sqrt{33}} {2}  

<em>Find the values of y</em>

For x=\frac{1-\sqrt{33}} {2}  

y=x+2

y=\frac{1-\sqrt{33}} {2}+2  ---->y=\frac{5-\sqrt{33}} {2}  

For x=\frac{1+\sqrt{33}} {2}  

y=x+2

y=\frac{1+\sqrt{33}} {2}+2  ---->y=\frac{5+\sqrt{33}} {2}  

therefore

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

5 0
3 years ago
Diego is trying to find the value of x in 5 times x = 35.
torisob [31]

Answer:

The answer is 7

Step-by-step explanation:

5x7=35

3 0
2 years ago
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