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KatRina [158]
2 years ago
6

What is the value of the lower quartile? a.0 b.8 c.6 d.2 thank you!

Mathematics
1 answer:
mr Goodwill [35]2 years ago
8 0

Answer:

D

Step-by-step explanation:

From the box- plot the left hand side of the box represents the lower quartile

that is Q_{1} = 2 → D


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a computer and printer a totoal cost $1132 the cost of the computer is three times the cost of the ptinter
zavuch27 [327]
Use a system of equations

C+P=1132
3P=C

Substitute C in first equation as
3P+P=1132
Simplify
4P=1132
Solve
P=1132/4
P=283

NOW SOLVE FOR C SUBSTITUTING P VALUE IN FIRST EQUATION

C+283=1132
C=1132-283
C=849


Printer = 283$
Computer = 849$
3 0
2 years ago
What is the prime factorization of 676
Blababa [14]

Answer:  2, 2, 13, 13

Step-by-step explanation: Prime number are numbers that can divide without remainder, This means that 676 is divisible by 2, 2, 13, 13, numbers.

4 0
2 years ago
Greetings. As a beginner, I'm struggling a bit to learn calculus. May I know what is the derivative of x to the power 4 step by
elena-14-01-66 [18.8K]

If you're just starting calculus, perhaps you're asking about using the definition of the derivative to differentiate x^4.

We have

\dfrac{d}{dx} x^4 = \displaystyle \lim_{h\to0} \frac{(x+h)^4 - x^4}h

Expand the numerator using the binomial theorem, then simplify and compute the limit.

\dfrac{d}{dx} x^4 = \displaystyle \lim_{h\to0} \frac{(x^4+4hx^3 + 6h^2x^2 + 4h^3x + h^4) - x^4}h \\\\ ~~~~~~~~ = \lim_{h\to0} \frac{4hx^3 + 6h^2x^2 + 4h^3x + h^4}h \\\\ ~~~~~~~~ = \lim_{h\to0} (4x^3 + 6hx^2 + 4h^2x + h^3) = \boxed{4x^3}

In general, the derivative of a power function f(x) = x^n is \frac{df}{dx} = nx^{n-1}. (This is the aptly-named "power rule" for differentiation.)

3 0
2 years ago
If on the unit circle C , the distance from P (1, 0) to the point T ( 5/13, 12/13 ) is x , determine the coordinates of the poin
Lorico [155]

Answer:

T' (\frac{5}{13},- \frac{12}{13})

Step-by-step explanation:

See the diagram attached.

This is a unit circle having a radius (r) = 1 unit.

So, the length of the circumference of the circle will be 2πr = 2π units.

Now, the point on the circle at a distance of x along the arc from P is T(\frac{5}{13},\frac{12}{13}).

Therefore, the point on the circle at a distance of 2π - x along the arc from P will be T' (\frac{5}{13},- \frac{12}{13}), where, T' is the image of point T, when reflected over the x-axis. (Answer)

6 0
3 years ago
Over the weekend koko spend a total of 16 hours working on school work she spent equal amounts of time working on 4 projects plu
MrMuchimi
Hours spent on project= p

4p+2=16 hours
4p=14
p=3 and a half hours
8 0
3 years ago
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