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bixtya [17]
3 years ago
8

Luiz and Bianca are brother and sister and go to the same school. Luiz walks to school using a footpath, a distance of 900 m, an

d he walks at 1.5 m/s. Bianca cycles to school along the roads, a distance of 1.5 km, and she cycles at 5 m/s. They both plan on arriving at school by 8.55 a.m. Who leaves home first and by how much?
Mathematics
1 answer:
dangina [55]3 years ago
5 0

Answer:

Luis leaves home first and he leaves 5 minutes before Bianca

Step-by-step explanation:

dL (distance travelled by Luis) = 900 m

sL(Luis'd speed) = 1.5 m/s

tL = time taken by Luis = dL/sL =  900/1.5 = 600 seconds =  10 mins

So Luis would need to leave home at 8:45 am

dB = 1.5 km = 1500 m

sB = 5 m/s

tB = dB/sB = 1500/5 = 300 seconds = 5 minutes

So Biance would leave home at 8:50 am

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Answer:

The answer to your question is x = 6

Step-by-step explanation:

Equation                   5x + 3x - 6 = 42

Process

Step 1. Add 6 units in both sides

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Step 2. Simplify

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Step 3. Simplify like terms

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Step 4. Divide by 8 both sides

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Step 5. Simplify

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Constant of Proportionality = d/t = 90/2 = 45 mph

In short, Constant of Proportionality would be: 45 miles per hour.

Here, d/t = 45
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In short, Your Equation would be: d= 45t

Hope this helps!


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