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zheka24 [161]
3 years ago
7

14

Mathematics
1 answer:
kipiarov [429]3 years ago
5 0

Answer:

Jumper, y = 172

Shirt, x = - 105

Step-by-step explanation:

Let :

Shirt = x

Jumper = y

5x + 4y = 163 - - (1)

3x + 2y = 29 - - - (2)

Multiply (1) by 3 and (2) by 5

15x + 12y = 489 - - - (3)

15x + 10y = 145 - - - (4)

Subtract :

12y - 10y = 489 - 145

2y = 344

y = 344 / 2

y = 172

Put y = 172 in (3)

15x + 12(172) = 489

15x + 2064 = 489

15x = 489 - 2064

15x = - 1575

x = - 105

The values ;

Jumper, y = 172

Shirt, x = - 105

We weren't supposed to obtain a negative value, kindly check if the parameters given are correct.

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A committee of 3 members for the education board is to be selected from a pool of 6 prospective candidates – C, D, E, F, G, and H. Candidates C, D and E are male and the rest are females. At least, one of the selected candidates should have a minimum of 10 years cognate experience in the education sector. The committee should have at least one male and a female candidate. Each of the committee members should have studied a different course for a bachelor’s degree.

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One household is to be selected at random from a town. ​ ​The probability that ​the household has a cat is 0.20.2 . ​ ​The proba
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Answer:

There is a 50% probability that the household has a dog, given that the household has a ​cat.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a household has a cat.

B is the probability that a household has a dog.

We have that:

A = a + (A \cap B)

In which a is the probability that a household has a cat but not a dog and A \cap B is the probability that a household has both a cat and a dog.

By the same logic, we have that:

B = b + (A \cap B)

The probability that the household has a cat or a dog is 0.5

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The probability that ​the household has a cat is 0.2.

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So

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What is ​the probability that the household has a dog, given that the household has a ​cat?

20% of the households have a cat, and 10% have both a cat and a dog. So

P = \frac{A \cap B}{A} = {0.1}{0.2} = 0.5

There is a 50% probability that the household has a dog, given that the household has a ​cat.

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2 years ago
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