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Nastasia [14]
2 years ago
5

Which of the following examples illustrates ordinal numbers?

Mathematics
1 answer:
Margaret [11]2 years ago
6 0

Answer:

30-5×2 of 3+(19-3) ÷8

Step-by-step explanation:

30-5×6+(19-3)÷8

30-5×6+16÷8

30-30+8

38-30

8

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Class records at rockwood college indicate that a student selected at random has probability 0.75 of passing french 101. for the
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To get the probability of two individual events both occurring, you have to multiply the probabilities of their individual events occurring. Therefore in this problem, the probability that a student selected at random will pass both French 101 and French 102 is 0.683 (.75 x .91). The answer is already rounded to three decimal places.

4 0
4 years ago
Read 2 more answers
Brainliest will be added
Alex17521 [72]

Answer:

5, -\frac{1}{10}, -5\frac{4}{8}

Step-by-step explanation:

If you convert each of these to a decimal, you will get:

-\frac{1}{10} = -0.1

-5\frac{4}{8} = -5.5

and then 5.

So, 5 is the greatest number, followed by -0.1, and -5.5 is the least.

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3 years ago
AAA construction company increases their work force from 12 workers to 20 workers in a year. What is the approximate percent inc
Sonbull [250]

Answer:

66.67

Step-by-step explanation:

20-12=8

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7 0
3 years ago
Here is the histogram of a data distribution. All class widths are 1.
JulsSmile [24]
Median is 6 so your answer is C
8 0
4 years ago
Suppose the supply and demand for a certain textbook are given by ​supply: p equals one half q squared comma ​demand: p equals n
vampirchik [111]

Answer:

Demand quantity: 6.3246

Supply quantity: 4.4721

Step-by-step explanation:

Supply equation:

p = (1/2) * q^2

Demand equation:

p = -(1/2) * q^2 + 30

(p is the price, q is the quantity)

If the price p is equal to 10, then we can calculate:

Supply quantity:

10 = 0.5 * q^2

q^2 = 20

q = 4.4721

Demand quantity:

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0.5 * q^2 = 20

q^2 = 40

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3 years ago
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