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kirza4 [7]
3 years ago
14

Solve for w k=2b-5w/3k

Mathematics
2 answers:
nlexa [21]3 years ago
7 0
k = \frac{2b - 5w}{3k}
3k^{2} = 2b - 5w
3k^{2} + 5w = 2b
5w = 2b - 3k^{2}
w = \frac{2}{5}b - \frac{3}{5}k^{2}
Westkost [7]3 years ago
7 0

Answer:

b = \frac{2b - 3k^{2} }{5}

Step-by-step explanation:

To solve for w in this equation;

k = \frac{2b - 5w}{3k}

This implies we have to make w the subject of the formula.

To make w subject of the formula, first we cross multiply.

3k  × k  =  2b  -  5w

3k²  =   2b   -5w

Now we will subtract  2b from both- side of the equation

3k²   - 2b  = -5w

we want to make the right hand side of the equation positive, to do that , we will just multiply through by minus sign.  The equation becomes;

-3k²   +   2b   = 5w

We can rearrange the equation;

2b -  3k²   =    5w

5w  =  2b  - 3k²

Then we will now divide both-side of the equation by 5

\frac{5w}{5}  =    \frac{2b - 3k^{2} }{5}

In the left side of the equation, the 5 at the  numerator will cancel out the 5 at the denominator.

Hence;

w  =   \frac{2b - 3k^{2} }{5}

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Since this is a right triangle (meaning one of the angles is 90°), and the other angle is given (57°), simply subtract these two values from 180° to get 180-(57+90)=33\textdegree.

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\frac{\sin(A)}{a} =  \frac{\sin(B)}{b}

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