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Korolek [52]
3 years ago
7

What is the equation of the line that has a slope of 4 and passes through the point (3, -10?

Mathematics
1 answer:
irga5000 [103]3 years ago
3 0
Hello 
the equation is y = ax+b
a the slop    a = 4
y = 4x+b
the line <span>passes through (3, -10) :  -10 = 6(3)+b
b = -28
</span>the equation is y = 6x-28
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Bearing in mind that the surface area of a 3D object is the total area of its surface (that is the sum of the areas of its faces), we can count the number of distinct shapes in each figure, calculate their areas and add them up. Be careful not to add the faces that are "inside".

<u>Figure 1</u>

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<u>Figure 2</u>

Its surface area consists of 6 squares of 5x5feet^2,  3 rectangles of 17x5feet^2, 1 rectangle of 13x5feet^2 and 2 triangles of base 12 feet and height 5 feet. So, its surface area is (17x5x3+6x5x5+13x5+12x5x2:2)feet^2 = 530feet^2

<u />

<u>Figure 3</u>

Its surface area consists of 2 rectangles of 12.5x5feet^2, 1 rectangle of 11x5feet^2, 2 triangles of base 12 feet and height 5 feet, 1 rectangle of 11x13feet^2, 2 rectangles of 12.5x11feet^2 and 1 rectangle of 12x11feet^2.

So, its surface area is (2x12.5x5+11x5+2x12x5:2+11x13+2x12.5x11+12x11)feet^2 = 790feet^2

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