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Naya [18.7K]
4 years ago
8

M^3+9m Factoring. Please help

Mathematics
2 answers:
Verdich [7]4 years ago
7 0
M^3 + 9m =

There is a common factor of m.

= m(m^2 + 9)

That is the complete factorization.
m^2 + 9 is a sum of two squares which is not factorable.

Answer: m(m^2 + 9)
shusha [124]4 years ago
7 0
M^3 + 9m 

Factor:

M^3 + 9m 

= m(m^2 + 9)

Answer:
m(m^2 + 9)




Hope that helps!!!!
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Answer:

Step-by-step explanation:

Partindo do pressuposto de que você pode ter coberturas duplas e triplas do mesmo item, o cálculo é relativamente simples. Para calcular as combinações possíveis; deve-se multiplicar as coberturas disponíveis pelo número total de coberturas permitidas. Este cálculo é semelhante a como olhamos para diferentes sistemas de contagem de base. Normalmente contamos com decimais (base 10), portanto, o número de combinações, se usar 3 dígitos, seria calculado por 10 x 10 x 10.

10x10 = 100

100x10 = 1000 combinações (0 a 999)

Sua pergunta sobre coberturas de pizza é a mesma, mas assumindo um sistema de numeração de base 12, então 12x12x12 ou 12³

Portanto, 1.728 combinações incluindo 0 (sem coberturas?) E também incluindo 12 ocasiões em que todas as 3 coberturas seriam iguais. Se esses cenários de pessoas forem restritos de modo que você só possa ter coberturas duplas máximas, etc., então essas combinações devem ser removidas (subtraídas do total de combinações permitidas).

Espero ter ajudado você a entender os princípios, então você deve ser capaz de trabalhar a partir disso, de muitas outras soluções semelhantes

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Justin Bieber had $815 in his savings account. He wants to keep at least $150 in the account
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Divide (28x5 + 29x4 + 5x3 + 86x2 + 56x + 53) by (–4x – 7) using synthetic division.
bixtya [17]

Answer:

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Step-by-step explanation:

Given the division problem, (28x⁵ + 29x⁴ + 5x³ + 86x² + 56x + 53) by (–4x – 7), find the solution in the attachment below.

The polynomial of a function is expressed as P(x) = Q(x) + R(x)/D(x)

Q(x) is the quotient

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Substituting this functions in the polynomial P(x);

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