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3 years ago

M^3+9m Factoring. Please help

2 answers:

7 0

M^3 + 9m =

There is a common factor of m.

= m(m^2 + 9)

That is the complete factorization.
m^2 + 9 is a sum of two squares which is not factorable.

Answer: m(m^2 + 9)

shusha [124]3 years ago

7 0

M^3 + 9m

Factor:

M^3 + 9m

= m(m^2 + 9)

Answer:
m(m^2 + 9)

Hope that helps!!!!

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It takes a train 60 seconds to completely drive through a bridge of 1260 m, and 90 seconds to completely drive through a tunnel

Olegator [25]

The length of train is 120 meters

The speed of train is 25 meter per second

Solution:

The speed is given by formula:

$speed = \frac{distance}{time}$

Given that,

It takes a train 60 seconds to completely drive through a bridge of 1260 m

And 90 seconds to completely drive through a tunnel of 2010 m

Let the length of the train be "x"

The total distance travelled by the train across the bridge is given by:

total distance = x + 1260 + x = 2x + 1260

[ here we use x + x to represent that train completely drives through bridge ]

The time taken is given as 60 seconds

Therefore, the speed is given as:

$speed = \frac{2x+ 1260}{60}$

The total distance travelled by the train through the tunnel is given by:

total distance = x + 2010 + x = 2x + 2010

The time taken is given as 90 seconds

Therefore, the speed is given as:

$speed = \frac{2x+ 2010}{90}$

The speed of the train was the same in both cases.

Equate both speeds

$\frac{2x+ 1260}{60} = \frac{2x+ 2010}{90}$

$\frac{x+630}{30} = \frac{x+1005}{45}$

$45(x+630) = 30(x+1005)\\\\45x + 28350 = 30x + 30150\\\\45x - 30x = 30150 - 28350\\\\15x = 1800\\\\x = 120$

Thus length of train is 120 meters

Find the speed of train:

$speed = \frac{2x+ 1260}{60}\\\\speed = \frac{2(120) + 1260)}{60}\\\\speed = 25$

Thus speed of train is 25 meter per second

5 0

3 years ago

What is the range of the relation?

tia_tia [17]

The correct answer is (-2,1,2,8)

The range are the y- values

The explanation:

The range is the set of all second elements of ordered pairs (y-coordinates). Only the elements "used" by the relation or function constitute the range.

Hope this helped you :D

7 0

3 years ago

Can anybody help with this one ...... ?

VLD [36.1K]

Answer:The answer is choice 3

Step-by-step explanation: