Solve for k J = k^2/4 (There can be multiple answers)

Mathematics

1 answer:

Makovka662 [10]4 years ago

8 0

Answer:

The first option is the answer (k = +/- 2 square root of J)

Step-by-step explanation:

Since you need to leave k by itself, You multiply both sides by 4 which will leave you with 4J=k^2. To get rid of the square(^2), you need to square root both sides which will leave k by it self. So now you have 4J inside the square root = k. The last step is to take the square root of 4 (which is + or -2) and put it outside the square root sign, leaving J inside the square root.

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The function C(x) = 29x + 54.5 represents the cost (in dollars) of cable for x months, including $54.50 installation fee. How ma

Ratling [72]

Hey there!!

Given equation :

... c(x) = 29x + 54.5

In this equation $54.50 is installation fee and this would remain as a constant. ( This value wouldn't change ).

'x' is represented as the number of months.

The total cost or c(x) is given as $344.50

Getting this into equations :

... 344.50 = 29x + 54.5

Subtracting 54.5 on both sides :

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Dividing by 29 on both sides :

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Hence, the number of months is 10.

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