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Natali5045456 [20]
3 years ago
12

Consider an industrial process in the textile industry in which strips of a particular type of cloth are being produced. these s

trips are defective in two ways, length and nature of texture. for the case of the latter, the process of identification is very complicated. it is known from historical information on the process that 10% of the strips fail the length test, 5% fail the texture test and only 0.8% fail both tests. if a strip is selected randomly from the process, and a quick measurement identifies it as failing the length test, what is the probability that it is texture defective?
Mathematics
1 answer:
Leviafan [203]3 years ago
6 0

L: length defective<span>, T </span>: texture defective.

Given that the strip is length defective, the probability that this strip is texture defective is given by

<span><span>P (TL) =P (T ∩ L)=0.008= 0.08.</span><span>P (L)0.1</span><span>|  www.imali.info</span></span>
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What's the approximate area of a segment of a circle with a height 6 m and the length of the chord is 20 m? Round your answer to
yuradex [85]
Hello!

The Correct Answer to this would be 100%:

Option "85.4".

(Work Below)

Given:
height = 6m
chord = 20 m

We need to find the radius of the circle.

20 m = 2 √ [ 6m( 2 x radius - 6 m ) ] 
20 m / 2 = 2 √[ 6m( 2 x radius - 6 m ) ] / 2 
10 m = √ [ 6m( 2 x radius - 6 m ) ] 
(10 m)² = √[ 6m( 2 x radius - 6 m ) ] ² 
100 m² = 6 m( 2 x radius - 6 m ) 
100 m² = 12 m x radius - 36 sq m 
100 m² + 36 m² = 12 m x radius - 36 m² + 36 m² 
136 m² = 12 m x radius 
136 m² / 12 m = 12 m x radius / 12 m 
<span>11.333 m = radius 
</span>
the area beneath an arc: 

Area = r² x arc cosine [ ( r - h ) / r ] - ( r - h ) x √( 2 x r x h - h²<span> ). 
</span>
r² = (11.333 m)² = 128.444 m² 
r - h= 11.333 m - 6 m = 5.333 m 
r * h = 11.333 m x 6 m = 68 m²

Area = 128.444 m² x arc cosine [ 5.333 m / 11.333 m ] - 5.333 m x √[ 2 x 68 m² - 36 m² ] 

Area = 128.444 m² x arc cosine [ 0.4706 ] - 5.333 m x √ [ 100m² ] 

Area = 128.444 m² x 1.0808 radians - 5.333 m x 10 m 

Area = 138.828 m² - 53.333 m² 

Area = 85.4 m<span>²
</span>

Hope this Helps! Have A Wonderful Day! :)


And as Always...

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Unit 3 | Lesson 9
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