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Westkost [7]
3 years ago
10

A study of 2500 randomly selected students of a major university showed that 300 students tried to turn in work late to at least

one instructor. What is the probability of a student turning in the work on time? O A. 0.136 B. 0.12 O C. 0.88 D. There is not enough information given to solve the problem.​
Mathematics
1 answer:
dsp733 years ago
4 0

Answer:

C

Step-by-step explanation:

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I’m completely lost. Answer?
aliya0001 [1]
I think it's true because its the same data set just put in order backwards.


Hope this helps!! :-)
3 0
3 years ago
Hellpp please 20 points for that​
Sergio [31]

Answer:

a) 12cm

b) 360cm²

c) 2160cm cubed

Step-by-step explanation:

a)

you would use Pythagoras theorem  for A

so half of 18 is 9

15² - 9² = 144

the square root of 144 is 12

the height is 12cm

b)

18 x 20 = 360cm²

c)

csa x L

csa = b x h divide by 2

18 x 12 = 216cm²/2 = 108cm²

108xm² x 20cm = 2160cm cubed

8 0
2 years ago
Does anyone know how to solve this?
KATRIN_1 [288]

Answer:

<30,-20>

Step-by-step explanation:

4u + 2v

4< 6,-4> + 2< 3,-2>

<24,-16> + < 6,-4>

<30,-20>

4 0
2 years ago
the graph of y=e^tanx-2 crosses the x axis at one point in the interval [0,1]. What is the slope of the graph at this point? I g
Svetlanka [38]
Y = e^tanx   -   2

To find at which point it crosses x axis we state that y= 0

e^tanx   - 2 = 0 
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061

to find slope at that point first we need to find first derivative of funtion y.

y' = (e^tanx)*1/cos^2(x)

now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
3 0
2 years ago
1. Given points A(3, -5) and B(19, -1), find the coordinates of point C that sit 3/8 of the way along line AB, closer to A than
zaharov [31]

1. C(x, y) = (7.3, –3.9)

2. C(x, y) = (17, –1.5)

Solution:

Question 1:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction \frac{3}{8}.

Point divides segment in the ratio formula:

$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)

Here, x_1=3, y_1=-5, x_2=19, y_2=-1 and m = 3, n = 8

$C(x, y)=\left(\frac{3\times19+8\times3}{3+8} , \frac{3\times(-1)+8\times(-5)}{3+8}\right)

           $=\left(\frac{57+24}{11} , \frac{-3-40}{11}\right)

           $=\left(\frac{81}{11} , \frac{-43}{11}\right)

C(x, y) = (7.3, –3.9)

Question 2:

Let the points are A(3, –5) and B(19, –1).

C is the point that on the segment AB in the fraction \frac{3}{8}.

Point divides segment in the ratio formula:

$C(x, y)=\left(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n}\right)

Here, x_1=3, y_1=-5, x_2=19, y_2=-1 and m = 7, n = 1

$C(x, y)=\left(\frac{7\times19+1\times3}{7+1} , \frac{7\times(-1)+1\times(-5)}{7+1}\right)

           $=\left(\frac{133+3}{8} , \frac{-7-5}{8}\right)

           $=\left(\frac{136}{8} , \frac{-12}{8}\right)

C(x, y) = (17, –1.5)

8 0
3 years ago
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