Answer:
The answer to your question is below
Step-by-step explanation:
4.-
4a. 72
_<u>x 9</u>
638
4b. The error this student is doing is that he multiplies the first number but he must add the decenes of this result to the result of the multiplication of the second number and he is not doing that.
4c.- I told him the correct way to solve multiplications.
a) Multiply the first number and only write the units.
b) If the are decenes add then to the units of the result of the multiplication of the second number.
Example
72 9 x 2 = 18
<u>x9 </u> Just write the 8
8
72
<u>x 9</u>
648 9 x 7 = 63 + 1 from the previous operation
= 64
The end behavior of the function is the one in option C.
<em>"One end increases and one end decreases"</em>
<h3>
What can we say about the end behavior?</h3>
Here we have the function:
f(x) = -ln(2x) + 4.
Remember that for the natural logarithm, as x tends to zero the function tends to negative infinity.
And as x tends to infinity, the natural logarithm tends to infinity.
So, for our function where we have a negative sign before the logarithm, as x tends to zero the function tends to infinity and as x tends to infinity the function tends to zero.
Then the correct option is C:
<em>"One end increases and one end decreases"</em>
If you want to learn more about end behaviors:
<em>brainly.com/question/1365136</em>
<em>#SPJ1</em>
Answer:
42.5 if rounding 43 for B
Step-by-step explanation:
P is the variable so put 100 under it
Then on the first empty fraction put 17/40
Cross multiply
You will get 40p=17x100
So then you multiply 17 by 100
1700
divided both sides by 40
Get the variable alone
Divide 1700 by 40
get 42.5
If your teacher is as annoying as mine round to 43
Answer:
y is the dependent variable
Step-by-step explanation:
Answer:
Wavelengths of all possible photons are;
λ1 = 9.492 × 10^(-8) m
λ2 = 1.28 × 10^(-6) m
λ3 = 1.28 × 10^(-6) m
λ4 = 4.04 × 10^(-6) m
Step-by-step explanation:
We can calculate the wavelength of all the possible photons emitted by the electron during this transition using Rydeberg's equation.
It's given by;
1/λ = R(1/(n_f)² - 1/(n_i)²)
Where;
λ is wavelength
R is Rydberg's constant = 1.0974 × 10^(7) /m
n_f is the final energy level = 1,2,3,4
n_i is the initial energy level = 5
At n_f = 1,.we have;
1/λ = (1.0974 × 10^(7))(1/(1)² - 1/(5)²)
1/λ = 10535040
λ = 1/10535040
λ = 9.492 × 10^(-8) m
At n_f = 2,.we have;
1/λ = (1.0974 × 10^(7))(1/(2)² - 1/(5)²)
1/λ = (1.0974 × 10^(7))(0.21)
1/λ = 2304540
λ = 1/2304540
λ = 4.34 × 10^(-7) m
At n_f = 3, we have;
1/λ = (1.0974 × 10^(7))(1/(3)² - 1/(5)²)
1/λ = (1.0974 × 10^(7))(0.07111)
1/λ = 780373.3333333334
λ = 1/780373.3333333334
λ = 1.28 × 10^(-6) m
At n_f = 4, we have;
1/λ = (1.0974 × 10^(7))(1/(4)² - 1/(5)²)
1/λ = (1.0974 × 10^(7))(0.0225)
1/λ = 246915
λ = 1/246915
λ = 4.04 × 10^(-6) m
