Question

PLEASE HELP ITS MATH

Answer 1

Answer:

y=[-4]x+[10]

Step-by-step explanation:

For a line to be perpendicular to another it must have the reverse reciprocal of the opposite line, to find the reverse reciprocal you take your slope, flip the numerator and denominator, and multiply it by -1.

The slope $\frac{1}{4}$ turns into $\frac{4}{1}$ and is then multiplied by -1 to become $\frac{-4}{1}$ which can be simplified down to: $-4$

Now that we know the slope we need the line to pass through a point, so we will use point slope form:

$y-y1=m(x-x1)$
Substitute in our slope and point values:

$y-2=-4(x-2)$

Now solve for y:

$y-2=-4(x-2)\\y-2=-4x+8\\y=-4x+10$

Then you will find that line $y=-4x+10$ runs perpendicular to $y=\frac{1}{4}x-8$ and intersects point (2,2).