A' = (- 3, 0 )
(x, y ) → (x - 5, y + 2 ) means subtract 5 from the original x-coordinate and add 2 to the original y- coordinate
A(2, - 2 ) → A'(2 - 5, - 2 + 2 ) → A'(- 3, 0 )
Answer:
BD = 4.99 units
Step-by-step explanation:
Consider the triangle ABD only. The angle formed is 31 degrees which occurs between two sides that are AD and BC. We know that for a right angled triangle, the angle can always be taken as an angle between hypotenuse and base. Thus, The perpendicular sides is then 3 units, where base is BD and Hypotenuse is AD Using formula for tanθ tanθ = Perpendicular/Base tan31 = 3/BD 0.601 = 3/BD BD = 3/0.601 BD = 4.99 units
Step-by-step explanation:
<em><u>bc</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
9514 1404 393
Answer:
38.5°
Step-by-step explanation:
You are given all three side lengths of the relevant triangle, so the Law of Cosines can be used to find any desired angle. If we call the desired angle C, then that law tells you ...
C = arccos((a² +b² -c²)/(2ab))
where a and b are the triangle side lengths adjacent to the angle of interest, and c is the side opposite. Here, 'a' and 'b' are the pole and cable lengths, and 'c' is the distance of the stake from the pole.
C = arccos((35² +48² -30²)/(2·35·48)) = arccos(2629/3360)
C ≈ 38.515°
The cable makes an angle of about 38.5° with the pole.
Answer:
c
Step-by-step explanation:
it is because in (a) the square root of 112. is 10.58 which is in between 10 and 11
(B) the square root of 180 is 13.42 which is between 13&14
(c) the square root of 12 is 3.46 which is not between 4&5
