Help i did the first part and id.k the rest.....

If the filling equipment is functioning properly what is the probability that the volume of oil in a randomly selected barrel wi

Sophie [7]

Answer:

$P(X>55.4)=P(\frac{X-\mu}{\sigma}>\frac{55.4-\mu}{\sigma})=P(Z>\frac{55.4-55}{0.5})=P(Z>0.8)$

$P(Z>0.8)=1-P(Z\leq 0.8)$

$P(Z>0.8)=1-0.788=0.212$

Step-by-step explanation:

Assuming this previous info : "Trucks carry barrels of crude oil from a port in Texas to a distributer in New Mexico on long trailers. Filling equipment is used to fill the barrels with the oil. When functioning properly, the actual volume of oil loaded into each barrel by the filling equipment at the port is approximately normally distributed with a mean of 55 gallons and a standard deviation of 0.5 gallons. If the mean is greater than 55.4 gallons, the filling mechanism is overfilling."

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the amount filling of a population, and for this case we know the distribution for X is given by:

$X \sim N(55,0.5)$

Where $\mu=55$ and $\sigma=0.5$

We are interested on this probability

$P(X>55.4)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>55.4)=P(\frac{X-\mu}{\sigma}>\frac{55.4-\mu}{\sigma})=P(Z>\frac{55.4-55}{0.5})=P(Z>0.8)$

And we can find this probability using the complement rule:

$P(Z>0.8)=1-P(Z\leq 0.8)$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(Z>0.8)=1-0.788=0.212$

8 0

3 years ago

Ingrid Nilsen purchased a $4,000 hydroponic system for her garden. The down payment is 20%, and the

Cerrena [4.2K]

The purchase of the hydroponic system by Ingrid Nilsen for $4,000 with a 20% down payment at 10% APR for 36 months, and the related calculations, are as follows:

a) down payment = $800.00 ($4,000 x 20%)

b) amount financed = $3,200 ($4,000 - $800)

c) monthly payment = $103.25

d) total amount repaid = $4,517

e) finance charge = $517

<h3>How is periodic payment computed?</h3>

The amount of the periodic payment, finance charge, and total repayment can be computed using an online finance calculator as follows:

<h3>Data and Calculations:</h3>

Auto Price = $4,000

Loan Term = 36 months

Interest Rate = 10%

Down Payment = $800 ($4,000 x 20%)

Monthly Payment = $103.25

Total Loan Amount $3,200.00

Upfront Payment = $800.00 ($4,000 x 20%)

Total of 36 Loan Payments = $3,717. ($103.25 x 36)

Total Loan Interest = $517

Total Cost (price, interest, tax, fees) = $4,517

Thus, Ingrid Nilsen repaid a total of $4,517 with $517 in interest (finance charge).

Learn more about periodic payments at brainly.com/question/13098072

#SPj1

5 0

2 years ago

What is the midpoint M of that line segment?

topjm [15]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ T(\stackrel{x_1}{6}~,~\stackrel{y_1}{3})\qquad U(\stackrel{x_2}{6}~,~\stackrel{y_2}{9}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{6+6}{2}~~,~~\cfrac{9+3}{2} \right)\implies \left( \cfrac{12}{2}~~,~~\cfrac{12}{2} \right)\implies \stackrel{M}{(6,6)}$

3 0

3 years ago

Please answer the following questions

laila [671]

Answer:

4a) 110 square centimetres

4b) 127 square centimetres

6) 292 square centimetres

8) 800 tiles

Step-by-step explanation:

4. We need to find the area of the large rectangle and then deduct the area of the unshaded part:

a) The large rectangle has dimensions 12 cm by 15 cm. Its area is:

A = 12 * 15 = 180 square centimetres

The unshaded part has a length of 15 - (3 + 2) cm i.e. 10 cm and a width of 7 cm. Its area is:

a = 10 * 7 = 70 square centimetres

Therefore, the area of the shaded part is:

A - a = 180 - 70 = 110 square centimetres

b) The large rectangle has dimensions 13 cm by 11 cm. Its area is:

A = 13 * 11 = 143 square centimetres

The unshaded part has dimensions 8 cm by 2 cm. Its area is:

a = 8 * 2 = 16 square centimetres

Therefore, the area of the shaded part is:

A - a = 143 - 16 = 127 square centimetres

6. The background area of the space not covered by the photograph is the area of the frame minus the area of the photograph.

The frame has dimensions 24 cm by 18 cm. Therefore, its area is:

A = 24 * 18 = 432 square centimetres

The photograph has dimensions 14 cm by 10 cm. Therefore, its area is:

a = 14 * 10 = 140 square centimetres

Therefore, the background area of the space not covered by the photograph is:

A - a = 432 - 140 = 292 square centimetres

8) The floor has dimensions 8 m by 4 m. The area of the floor is:

A = 8 * 4 = 32 square centimetres

Each square tile has dimensions 20 cm by 20 cm. In metres, that is 0.2 m by 0.2 m. The area of each tile is:

a = 0.2 * 0.2 = 0.04 square metres

The number of tiles that are needed is the area of the floor divided by the area of each tile:

A / a = 32 / 0.04 = 800 tiles

4 0

4 years ago

Pattern x: Starts at 0. Rule: Add 3.

raketka [301]

I think (0,0) is the only one that starts at 0 for both x and y and stay the same if the add the 3 to x and 6 to y.

5 0

4 years ago