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jenyasd209 [6]
4 years ago
9

You deposit 700$ in an account with an annual internet rate of 4% after 5 years

Mathematics
1 answer:
alex41 [277]4 years ago
6 0

Answer:

840

Step-by-step explanation:

Heres the easiest way to figure this out. You deposit $700 dollars into your account, correct? So, the annual interest rate is 4%. Take 700 dollars and multiply that by 4 percent. You get $28. So, EVERY. SINGLE. YEAR. you get 28$. So, multiply 28 by 5. Thats $140. Then, add 140 into 700, and you get 840.

Hope this helped!

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Pasadena Candle Inc. budgeted production of 45,000 candles for the year. Each candle requires molding. Assume that three minutes
REY [17]

Answer:

Step-by-step explanation:

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8 0
4 years ago
The region bounded by y=5/x, y=0, x=1, and x=3 is rotated about the x-axis. find the volume of the resulting solid.
brilliants [131]
Volume of Revolution  = \pi  \int\limits^b_a {y^{2}} \, dx
Volume of Revolution  = \pi \int\limits^3_1 { (\frac{5}{x})^{2}} \, dx
= \pi \int\limits^3_1 ({\frac{25}{x^{2}}) \, dx
= 25\pi \int\limits^3_1 ({\frac{1}{x^{2}}) \, dx
= 25\pi \int\limits^3_1 ({x^{-2}}) \, dx
= 25\pi \ ^{3} [-x^{-1}] _{1} 

= 25\pi\ ((-1/3) - (-1/1)) \\
= 25\pi\ (2/3) \\
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6 0
4 years ago
The Megasoft company gives each of its employees the title of programmer (P) or project manager (M). In any given year 70% of pr
Ne4ueva [31]

Answer:

it will take a programmer about 16.67 times to work before they are fired

Step-by-step explanation:

From the information given;

The transistion matrix for this study can be computed as:

       P          M         X

P     0.7      0.2        0.1

M     0        0.95     0.05

X      0        0            1

where;

The probability that the programmer remains a programmer = (P *P)

The probability that the programmer turns out to be a manager = (P*M)

The probability that the programmer is being fired = (P*X)

Thus, the required number of years prior to the moment being fired for an employee y(P), for programmer and y(M) for manager is represented by ;

y(P)=1+0.7y(P)+0.2y(M)

y(M)=1+ 0.95y(M).

0.05y(M)=1

y(M) = \dfrac{1}{0.05}

y(M) =20

y(P)=1+0.7y(P)+0.2y(M)

y(P) - 0.7y(P) = 1 + 0.2y(M)

0.3y(P) = 1 + 0.2(20)=1+4

0.3y(P) = 1 + 4

0.3y(P) =  5

y(P)=\dfrac{5}{0.3}

y(P)=16.67

Therefore, it will take a programmer about 16.67 times to work before they are fired

8 0
3 years ago
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Answer:

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Step-by-step explanation:

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