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2 years ago

If your born on 1900 how old would have you been on 2009?

Mathematics

2 answers:

KATRIN_1 [288]2 years ago

5 0

Answer:

109years old

Step-by-step explanation:

1900

1900 to 2000 is 100 years old

2000 to 2009 is 9 years old

100+9=109

Minchanka [31]2 years ago

3 0

Answer: 109 years old

Step-by-step explanation:

2009-1900=109

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Please give a step by step explanation with the reasons. Basically a proofs column. Thank you.

lesya692 [45]

Angle 4 equals angle 5, when all angles are equal and the triangles are similar

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2 years ago

What is the 72nd term of -27, -11, 5

FinnZ [79.3K]

Answer:

1109

Step-by-step explanation:

The first term is -27, and the common difference is 16.

The nth term is:

a = a₁ + d (n − 1)

a = -27 + 16 (n − 1)

a = -27 + 16n − 16

a = 16n − 43

The 72nd term is:

a = 16(72) − 43

a = 1109

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2 years ago

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Answer:

2.8744818177

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3 years ago

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If there are 30 girls and 50 boys In a class how what is the greatest Conan factor

dexar [7]

Answer:The greatest common factor is 15 to 10.

Step-by-step explanation:

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3 years ago

The area of a mirror is 225 Square inches, it's width is

Zepler [3.9K]

NO. The mirror will not fit in a space that is 15 inches by 16 inches

Solution:

Given that area of mirror is 225 square inches

$width = 13\frac{3}{4} \text{ inches }$

Converting the above mixed fraction we get,

$width = 13\frac{3}{4} = \frac{13 \times 4 + 3}{4} = \frac{55}{4} \text{ inches }$

Let us find the length of mirror

The area of mirror is given as:

area of mirror = length x width

Substituting the given values,

$225 = length \times \frac{55}{4}\\\\length = 225 \times \frac{4}{55}\\\\length = 225 \times 0.0727\\\\length = 16.36$

Thus length of mirror is 16.36 inches

Will the mirror fit in a space that is 15 inches by 16 inches?

NO. The mirror will not fit in a space that is 15 inches by 16 inches

Because length of mirror is 16.36 inches whereas the given space is 15 inches long

16.36 > 15 so the length of mirror will not fit inside the space

Also width of mirror is $\frac{55}{4} = 13.75$ inches which is less than the given space whose width is 16 inches

13.75 < 16 so the width of mirror will not fit inside the space

7 0

3 years ago