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stepladder [879]
3 years ago
14

If your born on 1900 how old would have you been on 2009?

Mathematics
2 answers:
KATRIN_1 [288]3 years ago
5 0

Answer:

109years old

Step-by-step explanation:

1900

1900 to 2000 is 100 years old

2000 to 2009 is 9 years old

100+9=109

Minchanka [31]3 years ago
3 0

Answer: 109 years old

Step-by-step explanation:

2009-1900=109

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Which expression represents”9 less than the product of 5 and a number n”?
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9 less means subtract

the product of 5 and the number n mea multiply 5 and n

D. 5n-9

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3 years ago
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Use the method of undetermined coefficients to find the general solution to the de y′′−3y′ 2y=ex e2x e−x
djverab [1.8K]

I'll assume the ODE is

y'' - 3y' + 2y = e^x + e^{2x} + e^{-x}

Solve the homogeneous ODE,

y'' - 3y' + 2y = 0

The characteristic equation

r^2 - 3r + 2 = (r - 1) (r - 2) = 0

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y = C_1 e^x + C_2 e^{2x}

For nonhomogeneous ODE (1),

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consider the ansatz particular solution

y = axe^x \implies y' = a(x+1) e^x \implies y'' = a(x+2) e^x

Substituting this into (1) gives

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For the nonhomogeneous ODE (2),

y'' - 3y' + 2y = e^{2x}

take the ansatz

y = bxe^{2x} \implies y' = b(2x+1) e^{2x} \implies y'' = b(4x+4) e^{2x}

Substitute (2) into the ODE to get

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Lastly, for the nonhomogeneous ODE (3)

y'' - 3y' + 2y = e^{-x}

take the ansatz

y = ce^{-x} \implies y' = -ce^{-x} \implies y'' = ce^{-x}

and solve for c.

ce^{-x} + 3ce^{-x} + 2ce^{-x} = e^{-x} \implies c = \dfrac16

Then the general solution to the ODE is

\boxed{y = C_1 e^x + C_2 e^{2x} - xe^x + xe^{2x} + \dfrac16 e^{-x}}

6 0
1 year ago
Usian bolt can run 100meters in 9.58 seconds . my car can drive 100kilometers an hour. which is faster, is it faster to travel 1
Mashcka [7]

Answer:

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The height of a a triangle is 6 centimeters more than double its base in centimeters. What is the height of the triangle, in cen
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H=2b+6 and you are told that b=8 so

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