Answer:
Step-by-step explanation:
Question
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.
perimeter of a triangle = AB+AC+BC
Using the distance formula
AB = sqrt(-2-5)²+(2-2)²
AB = sqrt(-7)²
AB =sqrt(49)
AB =7
BC = sqrt(-2+2)²+(2-5)²
BC = sqrt(0+3²)
BC =sqrt(9)
BC =3
AC= sqrt(-2-5)²+(2-5)²
AC= sqrt(-7)²+3²
AC =sqrt(49+9)
AC =sqrt58
Perimeter = 10+sqrt58
14 = 6x4 + b
14 = 24 + b
-10 = b
Hope this is accurate & helpful! Let me know if there are any errors or if you have any additional questions.
Answer:
Expression that can be written in the box on the other side of the equation will be x
Step-by-step explanation:
The left side of equation is:
Simplifying the equation we get:
An equation has no solution when, we cannot find the value of x.
So, The order side of equation can be x
i.e,
So, expression that can be written in the box on the other side of the equation will be x
I would say to check the 1st and 3rd
Answer:
8
Step-by-step explanation:
Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24
Factors of 32: 1, 2, 4, 8, 16, 32
GCF=8
