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amm1812
1 year ago
15

GCF if possible please show work.

Mathematics
1 answer:
nevsk [136]1 year ago
6 0

Answer:

8

Step-by-step explanation:

Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

Factors of 32: 1, 2, 4, 8, 16, 32

GCF=8

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Find the distance between the pair points (-2, -3) and (-12,-19)
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D = √(y2-y1)² + (x2-x1)²

d = √(-3+19)² + (-2+12)²

d = √16² + 10²

d = √256 + 100
d = √356
d = 18.87 units

In short, Your Answer would be: 18.87 units

Hope this helps!
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At a farming supply store 7 pounds of seed cost $153.37. If a farmer needed 4 pounds of seeds, how much would it cost him?​
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How can you solve problems involving equivalent expressions?
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How do I change z= -14+ 8i from rectangular form to polar form?
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3 years ago
Choose all that give the correct expression for the quantity described. The difference of nine times a number x and the quotient
ohaa [14]

Step-by-step explanation:

We are to get the expression for the following statements;

1) The difference of nine times a number x and the quotient of that number and 5.

The product of nine and a number x is expressed as;

=9 \times x\\= 9x

The quotient of that number and 5.

= \frac{x}{5}

The difference between both expression;

9x - \frac{x}{5}

Hence, the difference of nine times a number x and the quotient of that number and 5 is expressed as 9x - \frac{x}{5}

2) Eight more than the quotient of twelve and a number n

Quotient of twelve and a number n is expressed as:

\frac{n}{12}

Eight more than the resulting function is;

\frac{n}{12}+8

Hence eight more than the quotient of twelve and a number n is expressed as \frac{n}{12}+8

3) The product of a number and the quantity 'six minus the number' plus the quotient of eight and the number.

Let the number be x:

six minus the number is expressed as;

6-x

product of a number x and the quantity 'six minus the number is;

x(6-x)

quotient of eight and the number is;

\frac{8}{x}

Taking the resulting sum of the last two expression

x(6-x) + 8x

Hence the product of a number and the quantity 'six minus the number' plus the quotient of eight and the number is expressed as;

x(6-x) + 8x

4) Sum of three consecutive even integers. 2x + (2x + 2) + (2x + 4).

Let the first even number be 2x

The consecutive even numbers are gotten by adding 2 to the preceding number. The two consecutive even integers are 2x+2 and 2x+2+2

the sum of three consecutive even integers is expressed as;

= 2x +(2x+2)+(2x+2+2)\\=  2x+(2x+2)+(2x+4)

4 0
3 years ago
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