Answer:
greater that 90 but less than 180
Answer:
Step-by-step explanation:
The perimeter of a polygon is equal to the sum of all the sides of the polygon. Quadrilateral PTOS consists of sides TP, SP, TO, and SO.
Since TO and SO are both radii of the circle, they must be equal. Thus, since TO is given as 10 cm, SO will also be 10 cm.
To find TP and SP, we can use the Pythagorean Theorem. Since they are tangents, they intersect the circle at a , creating right triangles and .
The Pythagorean Theorem states that the following is true for any right triangle:
, where is the hypotenuse, or the longest side, of the triangle
Thus, we have:
Since both TP and SP are tangents of the circle and extend to the same point P, they will be equal.
What we know:
Thus, the perimeter of the quadrilateral PTOS is equal to
1 Subtract <span><span>yy</span>y</span> from both sides
<span><span><span>43−y=<span>x3</span>−5</span>43-y=\frac{x}{3}-5</span><span>43−y=<span><span>3</span><span>x</span><span></span></span>−5</span></span>
2 Add <span><span>55</span>5</span> to both sides
<span><span><span>43−y+5=<span>x3</span></span>43-y+5=\frac{x}{3}</span><span>43−y+5=<span><span>3</span><span>x</span><span></span></span></span></span>
3 Simplify <span><span><span>43−y+5</span>43-y+5</span><span>43−y+5</span></span> to <span><span><span>48−y</span>48-y</span><span>48−y</span></span>
<span><span><span>48−y=<span>x3</span></span>48-y=\frac{x}{3}</span><span>48−y=<span><span>3</span><span>x</span><span></span></span></span></span>
4 Multiply both sides by <span><span>33</span>3</span>
<span><span><span>(48−y)×3=x</span>(48-y)\times 3=x</span><span>(48−y)×3=x</span></span>
5 Regroup terms
<span><span><span>3(48−y)=x</span>3(48-y)=x</span><span>3(48−y)=x</span></span>
6 Switch sides
<span><span><span>x=3(48−y)</span>x=3(48-y)</span><span>x=3(48−y<span>)</span></span></span>
Size is continuous
screen type is qualitative
number of channels available is discrete
a simple way to get the coordinates of the vertex, is, the constant outside the bars is the y-coordinate of the vertex, and to get the x-coordinate, we can simply find what values of x makes the barred expression to 0, and we can do that by simply zeroing out the barred expression and solving for x.