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2 years ago

Why all samples of a given substance have the same intensive properties?

Chemistry

1 answer:

Karolina [17]2 years ago

4 0

Answer:

Every sample of a given substance has identical intensive properties because every sample has the same composition

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Which pair of elements below have +3 ionic change?<br> A. Al and Ga<br> B. Sc and Y

Vsevolod [243]

B I think Im not sure

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3 years ago

Question 2 (Multiple Choice Worth 2 points)

faust18 [17]

Answer:

$\pi$ r² x h

Explanation:

A can is cylindrical in nature. Using the formula of the volume of the can, we can find this unknown volume.

The volume of cylinder is given as:

Volume of a cylinder = Area x height

Volume of a cylinder = $\pi$ r² x h

Therefore density of the can;

Density = $\frac{mass}{volume}$

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2 years ago

A gas has a pressure of 3 atm at 350°C. What will its pressure be at 250°C? The volume and amount of gas is constant. Hint: Conv

vichka [17]

<u>We are given:</u>

P1 = 3 atm T1 = 623 K <em>(350 + 273)</em>

P2 = x atm T2 = 523 K <em>(250 + 273)</em>

<em />

<u>Solving for x:</u>

From the idea gas equation:

PV = nRT

since number of moles (n) , Volume (V) and the Universal Gas constant(R) are constants;

P / T = k (where k is a constant)

the value of k will be the same for a gas with variable pressure and temperature and constant moles and volume

Hence, we can say that:

P1 / T1 = P2 / T2

3 / 623 = x / 523

x = 523 * 3 / 623

x = 2.5 atm (approx)

Therefore, the final pressure is 2.5 atm

7 0

2 years ago

I’m not sure what the answer is

Sergio [31]

I believe it’s the third option
Chemically combined to make a new pure substance

7 0

3 years ago

Read 2 more answers

Need help !!!!! ASAP

gavmur [86]

<h2>Hello!</h2>

The answer is:

The new temperature will be equal to 4 K.

$T_{2}=4K$

We are given the volume, the first temperature and the new volume after the gas is compressed. To calculate the new temperature after the gas was compressed, we need to use Charles's Law.

Charles's Law establishes a relationship between the volume and the temperature at a gas while its pressure is constant.

Now, to calculate the new temperature we need to assume that the pressure is kept constant, otherwise, the problem would not have a solution.

From Charle's Law, we have:

$\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$

So, we are given the following information:

$V_{1}=500mL\\T_{1}=20K\\V_{2}=100mL$

Then, isolating the new temperature and substituting the given information, we have:

$\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$

$T_{2}=\frac{T_{1}}{V_{1}}*V_{2} \\$

$T_{2}=\frac{20.00K}{500mL}*100mL\\$

$T_{2}=4K$

Hence, the new temperature will be equal to 4 K.

$T_{2}=4K$

Have a nice day!

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3 years ago