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denis23 [38]
3 years ago
7

Each hydrogen atom contains ___ protons.

Chemistry
2 answers:
MA_775_DIABLO [31]3 years ago
7 0
1
8
1
2
Covalent
6
Inner
Sorry don’t understand the last question
Andrei [34K]3 years ago
7 0

Answer:

The last question is not complete. This is the possible question " How many atom of oxygen and hydrogen is in water molecule"?

The answers are:

1)    1 proton

2)   8 Neutrons

3)   1 Electrons

4)   2 electrons

5)   Ionic bond

6)   6 Electrons

7)   Inner or S orbit

8)   2 atoms of hydrogen and one atom of oxygen

Explanation:

Atomic number is the number of proton in the nucleus of an atom.

The proton number is equal to the number of electron of an atom.

The formula: mass number = proton number + neutron number  is used to calculate either the proton number or the neutron number of an atom.

The K shell contains 2 electrons in it's shell. The L shell contains 8 electron and the M shell also contains 8. Oxygen has 6 electrons in it's outermost shell while hydrogen has only one.

Ionic bond involves the sharing of electrons between two atoms bearing a negative and a positive charge. It exist between hydrogen and oxygen atom.

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Please Help Me!!!
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Answer:

The products are carbon dioxide and water

Explanation:

Step 1: Data given

Combustion = a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat. Combustion reactions must involve  O2  as one reactant.

Step 2: The complete combustion of C3H7OH:

For the combustion of 1-propanol, we need O2.

The products of this combustion are CO2 and H2O.

C3H7OH + O2→ CO2 + H2O

On the left side we have 3x C (in c3H7OH), on the right side we have 1x C (in CO2). To balance the amount of C, we have to multiply CO2 on the right side by 3

C3H7OH + O2→ 3CO2 + H2O

On the left side we have 8x H (in C3H7OH) and 2x on the right side (in H2O). To balance the amount of H, we have to multiply H2O, on the right side by 4.

C3H7OH + O2→ 3CO2 + 4H2O

On the left side we have 3x O (1x in C3H7OH and 2x in O2), on the right side we have 10x O (6x in CO2 and 4x in H2O).

To balance the amount of O on both sides, we have to multiply C3H7OH by 2, multiply O2 by 9. Then we have to multiply 3CO2 by 2 and 4H2O by 2. Now the equation is balanced.

2C3H7OH + 9O2→ 6CO2 + 8H2O

For 2 moles propanol, we need 9 moles of O2 to produce 6 moles of CO2 and 8 moles Of H2O

The products are carbon dioxide and water

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