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3 years ago

6

Two long parallel wires are a center-to-center distance of 4.90 cm apart and carry equal anti-parallel currents of 4.10 A. Find

the magnetic field intensity at the point P which is equidistant from the wires. (R = 6.00 cm).

1 answer:

algol133 years ago

4 0

Answer:

<em>The magnetic field intensity at the point P, equidistant from the wires is</em>

<em> 9.566 x </em> $10^{-5}$ <em> T</em>

Explanation:

The magnetic field intensity can be obtained by resolving the vertical and horizontal components of the magnetic field. The step by step calculation is contained in the pictures attached;

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So, the energy of the incoming photon hitting on the metal must be at least equal to this value.

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4 years ago

At the moment a hot cake is put in a cooler, the difference between the cakes and the cooler's

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3 years ago

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4 years ago

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Delicious77 [7]

Answer:

The length of the tube is 3.92 m.

Explanation:

Given that,

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$\gamma=1.01953$

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Put the value into the formula

$L'=\dfrac{4}{1.01953}$

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Hence, The length of the tube is 3.92 m.

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3 years ago