Answer:
onservation of energy
U top = K bottom
(m + m)*g*L = 1/2*I*?^2 where I = m*(L/2)^2 + m*L^2 = 1.25*m*L^2
So 2m*g*L = 1/2*1.25*m*L^2*?^2
So ? = sqrt(3*g*/(1.25*L) ) = sqrt(12g/5L)
Answer:
D
Explanation:
The friction force is the weight force times the coefficient of friction. So diving by the coefficient gives you the weight force which is equivalent to the normal force.
Answer:
q = 2.65 10⁻⁶ C
Explanation:
For this exercise we use Coulomb's law
F =
In this case they indicate that the load is of equal magnitude
q₁ = q₂ = q
the force is attractive because the signs of the charges are opposite
F = 
q = 
we calculate
q = 
q = 
Ra 7 10-12
q = 2.65 10⁻⁶ C
1. Physical size of Russia compared to other countries, despite a lack of visible borders from space.
2. Part of Russia's outline would likely be obscured by the various clouds and objects in the stratosphere; this would allow the astronaut to view potential cloud and weather patterns on earth.
3. An astronaut could see outlines of Russia's geography such as mountain ranges.
Hope that it helps :)
