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3 years ago

What is the composition of a DNA fragment?

Biology

1 answer:

Firlakuza [10]3 years ago

4 0

Answer:

DNA is formed by the union of many deoxyribonucleotides, it is composed of two long chains of polynucleotides, which are kept together due to the interactions of their nitrogenous bases.

Explanation:

DNA is the carrier of genetic information, it can therefore be said that genes are made up of DNA. Nucleotides are the monomeric units of DNA and RNA, also known as nucleic acids, which are responsible for storing and transmitting genetic information from one generation to another. The primary structure of DNA is the deoxyribonucleotide sequence of one of the strands. Genetic information is contained in the exact order of nucleotides

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Without the sun, there of been no life on earth. This is because the sun is a major source of all______ on Earth.

Dominik [7]

life ; living beings ; living life

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3 years ago

Kelley used to do three sets of squats one time per week. after three weeks she noticed she was less sore than when she started

Lemur [1.5K]

The principle underlying this change is called progression. This principle tells us that when your fitness level improves, your body has adjusted to your regular routine; thus, you will feel less sore than when you started the squats three weeks ago. During this time, your muscles have developed and your body has adopted to the stress brought about by your exercise.

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3 years ago

When a phosphate group is released ATP becomes

Marat540 [252]

This occurs when a molecule of adenosine diphosphate (ADP) uses the energy released during cellular respiration to bond with a thirdphosphate group, becoming amolecule of ATP. So the energy from cellular respiration is stored in the bond between the 2nd and 3rdphosphate group

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3 years ago

A tissue sampler that is being used for a medical procedure is placed inside a saline solution. Unknown to the medical team, the

solong [7]

Answer: Water will leave the cell and the cell will shrink.

Explanation:

Osmosis is the net movement of water from an area of low to high concentration of solutes through a semipermeable membrane. If none of the compartments contains solutes, then the water moves in either direction between the compartments. However, if we add a solute to one of the compartments, this will affect the probability of water molecules leaving that compartment and moving into the other compartment. The ability of water to move into or out of a cell is called tonicity. The tonicity of a solution is related to its osmolarity, which is the total concentration of all the solutes in the solution. A solution with low osmolarity has few solute particles per liter of solution, whereas a solution with high osmolarity has many solute particles per liter of solution. When two solutions with different osmolarities are separated by a membrane permeable to water but not permeable to solutes, water diffuses from the side with lower osmolarity to the side with higher osmolarity. So, solutions can be:

Hypotonic: The extracellular fluid has a lower osmolarity than the fluid inside the cell, it is hypotonic with respect to the cell, and the net flow of water will be into the cell.
Hypertonic: The extracellular fluid has a higher osmolarity than the cytoplasm of the cell, it is hypertonic with respect to the cell and water will flow out of the cell.
Isotonic: The extracellular fluid and the cell have the same osmolarity so there is no net movement of water.

If a cell is placed in a hypertonic solution, water will leave the cell and the cell will shrink due to the difference in pressure and may even die from dehydration.

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3 years ago

You are a botanist looking at the plant color in a new breed of Snapdragon. The two parent plants are Blue and Green and when yo

irakobra [83]

Answer:

Incomplete dominance is the inheritance pattern where the dominant allele did not mask the recessive allele completely and form a mix of both alleles. Here the inheritance is the incomplete inheritance. The ratio of F2 generation is 1:2:1.

Given:

R1R1 = 42

R2R2 = 39

R1R2 = 86

Total R1 alleles = 2*42+86 = 170

Total R2 alleles = 2*39+86 = 164

Total alleles = 334

Frequency of allele R1 = 170/334 = 0.51

Frequency of allele R2 = 164 / 334 = 0.49

Expected number of each phenotype:

Total population = 167

Blue = R1R1 = 0.51 * 0.51 * 167 = 43.44

Green = R2R2 = 0.49 * 0.49 * 167 = 40.10

Cyan = 2*R1*R2 = 2*0.51*0.49*167 = 83.46

Phenotype Observed(O) Expected (E) O-E (O-E)2 (O-E)2/E

Blue 42 43.44 -1.44 2.0736 0.0477

cyan 86 83.46 2.54 6.4516 0.0773

green 39 40.1 -1.1 1.2100 0.0302

Total 167 167 0.1552

Chi-square value = 0.155

Degrees of freedom = no. of phenotypes – 1

Df = 3-1 = 2

Critical value = 5.99

Chi-square value of 0.155 is less than the critical value of 5.99. So we accept the null hypothesis.

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3 years ago