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vagabundo [1.1K]
3 years ago
14

What is 6/3 as a mixed number?

Mathematics
1 answer:
Reptile [31]3 years ago
3 0
The mixed number of 6/3 is 2








Explanation








Nothing it’s just what it is
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The width and the length of a rectangle are consecutive even integers. If the width is decreased by 3 inches, then the area of t
Yuliya22 [10]

The original are would be 48.

Since we know that the length and width are two consecutive even integers, we can model them as follows:

Width = x

Length = x + 2

This works because no matter what even number is put in for x, the length will also be even.

Now we know if we subtract 3 from the width, we have a new rectangle that gives us an area of 24 inches. Therefore, our new triangle has the following:

Width: x - 3

Length: x + 2

Area: 24

And we can plug this into the equation.

Length* Width = Area

(x + 2)(x - 3) = 24

x^2 - x - 6 = 24

x^2 - x - 30 = 0

This is not a quadratic that we can factor to show the following:

(x - 6)(x + 5) = 0

This gives us the answers of x = 6 and x = -5. Since a side can't be negative, we throw out the x = -5 and the answer is x = 6.

So if we go back to the original rectangle, we know:

Width = x = 6

Length = x + 2 = 8

Area = 6*8 = 48

7 0
3 years ago
I have dyscalculia and I hate math. I am absolutely confused about multi step equations with fractions.
Galina-37 [17]

Answer:

If you have *dyslexia, then how do you know how to spell so well?

Step-by-step explanation:

7 0
2 years ago
Solve the inequality and graph the solution on the line provided. -20+5x >5
ZanzabumX [31]

Answer:

x>5

Step-by-step explanation:

-20+5x>5

5x>25

X>5

X=

--l----l----l----l----l----l----l----l----l

 6   7    8   9   10  11   12 ....   ∞

3 0
2 years ago
A walk-in medical clinic believes that arrivals are uniformly distributed over weekdays (Monday through Friday). It has collecte
allsm [11]

Answer:

The degrees of freedom are given by;

df =n-1= 5-1=4

The significance level is 0.1 so then the critical value would be given by:

F_{cric}= 7.779

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays

Step-by-step explanation:

For this case we have the following observed values:

Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100

For this case the expected values for each day are assumed:

E_i = \frac{100}{5}= 20

The statsitic would be given by:

\chi^2 = \sum_{i=1}^n \frac{(O_i-E_i)^2}{E_i}

Where O represent the observed values and E the expected values

The degrees of freedom are given by;

df =n-1= 5-1=4

The significance level is 0.1 so then the critical value would be given by:

F_{cric}= 7.779

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays

5 0
3 years ago
I need help with numbers 7-9 please
jolli1 [7]

Answer:

C

5(10)+10=60

-2(-5)+7=17

Step-by-step explanation:


7 0
3 years ago
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